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Dmitry_Shevchenko [17]
3 years ago
8

A rectangle has area 64 m2. Express the perimeter of the rectangle as a function of the length L of one of its sides. State the

domain of P
Mathematics
1 answer:
svp [43]3 years ago
3 0
A rectangle is a two-dimensional shape with two sets of equal, parallel sides. These dimensions are the length (L) and the width (W). The formula for the rectangle's area is the product of the two dimensions. The formula for perimeter is

P = 2L + 2W

Since
A = LW = 64
W = 64/L
Substituting to the formula for perimeter would be,

P = 2L + 2(64/L)
P = 2L + 128/L
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Step-by-step explanation:

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PLEASE SHOW WORK !!!
Fed [463]
For this, you have to understand the ratios of a 30,60,90 triangle. The ratio(in order) is x, x(sqrt 3), 2x (following the 30,60,90 pattern y'know). Well, we know the length of the hypotenuse, 4.2, so let's use ratios to figure the other sides out. The ratio of AC is x and the ratio of AB is 2x, so 2x/2=x=2.1. One side down. BC has a ratio of x(sqrt 3). We already know x so we can substitute it in. We get 2.1(sqrt 3). To calculate the area, use the formula 1/2(bh). Inputting the values in, we get 1/2(2.1*(2.1(sqrt 3)). This can be calculated to around 3.82. To calculate the perimeter, take the sum of the sides. By adding the sides together, we get about 9.98. Hope you can now understand how to do these kinds of questions.
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3 years ago
How many solutions does this linear system of equations have?
Irina18 [472]
It has infinite solutions
4 0
3 years ago
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7+ax-5x=3+2x-bx<br><img src="https://tex.z-dn.net/?f=7%20%20%2B%20ax%20-%205x%20%3D%203%20%2B%202x%20-%20bx" id="TexFormula1" ti
butalik [34]

Answer:

a = −bx+7x−4 over x


Step-by-step explanation:

solve for a:

7+ax−5x=3+2x−bx

add 5x to both sides:

ax−5x+7+5x=−bx+2x+3+5x

ax+7=−bx+7x+3

add -7 to both sides:

ax+7+−7=−bx+7x+3+−7

−bx+7x−4

lastly divide both sides by x.

7 0
3 years ago
May I please receive help?
san4es73 [151]

Answer: (175*π)yd^2

Step-by-step explanation:

If we find the total area enclosed by the outer circle, the subtract the area enclosed by the inner circle, the we inevitably get the area between the two regions.

The radius of the outer circle is 15yd + 5yd, which is 20yd. Use the formula for the area of a circle, A = pi*r^2. Therefore, the area enclosed by the outer circle is:

A=\pi* 20^2=400\pi

Now, the radius of the inner circle was stated to be 15yd. Do the same thing. Plug it into the formula:

A=\pi *15^2=225\pi

Subtract the two areas to find the shaded blue area. Hopefully this was intuitive by thinking of area as an enclosed region of space.

A=400\pi -225\pi =175\pi

8 0
3 years ago
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