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Svetach [21]
4 years ago
9

The midpoint of JK is M(6, 3). One endpoint is J(14, 9). Find the coordinates of endpoint K.

Mathematics
1 answer:
uysha [10]4 years ago
6 0
(x1 + x2 / 2) , (y1 + y2 /2)
so just sub in ur values
(6 + 14 /2) and (3+9/2)
so first add before dividing by2
(20/2) and (12/2)
then divide by 2
10 and 6
so endpoint k is
(10,6)
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Let f(x)=g(x)h(x), g(10)=-4, h(10)=560, g'(10)=0, and h'(10)=35. find f'(10)
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This question has extraneous info to trick you.
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