When n = 1, 2(1) + 1 = 3
When n = 2, 2(2) + 1 = 5
When n = 3, 2(3) + 1 = 7
When n = 4, 2(4) + 1 = 9
When n = 5, 2(5) + 1 = 11
Sum = 3 + 5 + 7 + 9 + 11 = 35
----------------------------------------------------
Answer: 35
----------------------------------------------------
The total of 2 buckets of popcorn and 3 boxes of candy would be $23.25
To answer this question you need to form a set of simultaneous equations and solve them. We can do this by saying that a bucket of popcorn = P, and a box of candy = C. Then we can say:
4P + 6C = 46.50
P + C = 9.75
There are then two possible ways to solve; you can either say that C = 9.75 - P using the second equation and then substitute it into the first, or you can multiply the second equation by either 4 or 6 to cancel out P or C.
I’m going to multiply the second equation by 4:
4P + 4C = 39
Now we can subtract this for, the first equation:
4P + 6C = 46.50
4P + 4C = 39
2C = 7.50
C = 3.75
Now we can substitute this value of C into one of the equations to find P:
P + C = 9.75
P + 3.75 = 9.75
P = 6
And now to answer the question, you just multiply P by 2 and C by 3 and add them together, which gives you $23.25
I hope this helps! Let me know if you have any questions :)
<span>Ishaan is 21, Christopher is 7
No actual question given, but I will assume that the question is "How old are they?". If that's the case, we can create two equations. I'll use I for Ishaan's age and C for Christopher's. I will also assume that there's been some formatting issues here and for some reason, numbers are repeated 3 times without any spaces. So
"Ishaan is 3 times as old as Christopher"
I = 3C
"is also 14 years older than Christopher
I = C + 14
Since both equations are equal to each other, let's set them equal. So
3C = C + 14
2C = 14
C = 7
So Christopher is 7. And we can use the equation I = C + 14 to get Ishaan's age. So
I = C + 14
I = 7 + 14
I = 21</span>
The answer is 5.83
Use the Pythagorean Theorem to calculate the 3rd side length.
a^2+b^2=c^2
3^2+5^2=c^2
I would say d that what i got.
