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gulaghasi [49]
4 years ago
15

3(c - 5) = 7c + c solve for c

Mathematics
1 answer:
AlladinOne [14]4 years ago
6 0

Hey there!!

First step we will need to take is to solve the distributive property.

We will solve 3 ( c - 5 )

= 3c - 15

The total equation :

3c - 15 = 7c + c

Combine the like term on the right side of the equation :

3c - 15 = 8c

Subtract 3c on both sides

-15 = 5c

Divide by 5 on both sides

-3 = c

The value of c is equal to -3

Hope my answer helps!!

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babymother [125]
4/5 divided by 2 = 2/5
2/5 + 1/3 = 11/15

ans: 11/15
3 0
3 years ago
Help me out <br>Answer required ​
dexar [7]

Answer:

a. rational

b. irrational

c. irrational

d. rational

e. rational

f. rational

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8 0
3 years ago
Activity
Sergio039 [100]

Answer:

A:

Dylan’s weight is d.

Twice Dylan’s weight is 2d.

Three pounds more than twice Dylan’s weight is 2d + 3.

So, the expression for Alan’s weight in terms of Dylan’s weight is 2d + 3.

B:

Dylan’s weight is d.

Three times Dylan’s weight is 3d.

Twelve less than three times Dylan’s weight is 3d − 12.

So, the expression for Bruce’s weight in terms of Dylan’s weight is 3d − 12.

C:

Cecil’s weight is the sum of Alan's weight and Bruce's weight.

Alan’s weight in terms of Dylan's weight is 2d + 3.

Bruce’s weight in terms of Dylan's weight is 3d − 12.

So, the expression for Cecil’s weight in terms of Dylan’s weight is (2d + 3) + (3d − 12).

D:

Cecil's weight is (2d + 3) + (3d − 12).

Find Cecil's weight by substituting Dylan’s weight (d = 45) into the expression above:

(2 × 45 + 3) + (3 × 45 − 12)

=  (90 + 3) + (135 − 12)

=  93 + 123

=  216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

E:

Yes, the expression can be simplified by using the Associative and Commutative Properties of addition and by combining the like terms in the expression.

F:

(2d + 3) + (3d − 12)

First remove the parentheses:

2d + 3 + 3d − 12.

Then group the like terms:

2d + 3d + 3 − 12.

Finally, add and subtract the like terms:

5d − 9.

The expression (2d + 3) + (3d − 12) simplifies to 5d − 9.

G:

Cecil’s weight in terms of Dylan’s weight is 5d – 9.

Find Cecil’s weight by substituting Dylan’s weight (d = 45) into the expression above:

(5 × 45) − 9

= 225 − 9

= 216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

H:

Yes, the answers are the same. The expression from part D is equivalent to the expression from part G.

I:

Bruce's weight in terms of Dylan’s weight is 3d − 12.

Alan's weight in terms of Dylan’s weight is 2d + 3.

So, the expression (3d − 12) − (2d + 3) represents how much more Bruce weighs than Alan.

J:

The expression is (3d − 12) − (2d + 3).

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

(3 × 45 − 12) − (2 × 45 + 3)

= (135 − 12) − (90 + 3)

= (123) − (93)

= 30.

Bruce weighs 30 pounds more than Alan weighs.

K:

The expression (3d − 12) − (2d + 3) simplifies to d − 15.

L:

The expression is d − 15.

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

45 − 15 = 30.

Bruce weighs 30 pounds more than Alan. This is the same answer as in part J.

Do not copy, it's the exact answer from edmuentum

5 0
3 years ago
If h(x) = 2x^2 , then h(-2) + 5=_________
Vaselesa [24]

Answer:

13

Step-by-step explanation:

Given the equation h(x) = 2x²

To solve for h(-2) + 5 then, we need to break the problem into two parts

First, we will solve for the function h(x) at x = -2

h(x) = 2x² so

h(-2) = 2(-2)²

h(-2) = 8

Knowing this, we can plug 8 into our original expression for h(-2)

8 + 5

This gives us 13

8 0
4 years ago
For the last showing of a movie, a theater sold full-price and discount tickets,the theater sold 130 full-price ticket for a tot
sveta [45]

Answer:

the cost of 1 full price ticket is $9.5

Step-by-step explanation:

For the last showing of a movie, a theater sold full-price and discount tickets,the theater sold 130 full-price ticket for a total of $1235 the total sales both types of tickets were $2395

Let x be the number of full price tickets and y be the number of discount tickets

the theater sold 130 full-price ticket for a total of $1235 the total sales

130 full price tickets sold for $1235

the cost of 1 full price ticket is

\frac{1235}{130}=9.5

the cost of 1 full price ticket is $9.5

4 0
3 years ago
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