Let x = 6.
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So say, we add "x" of the 60% saline solution, now, how much salt is in that solution? now 60% is salt but the rest is something else, but only salt is 60% of "x", or (60/100) * x, or 0.6x.
likewise, for the 10 Liters, if only 50% is salt, then is just (50/100) * 10 or 5.
now... let's check the water whilst we add "y" amount, the water has no salt at all, freshwater for that matter, so, salinity is 0%. or (0/100) * y or 0.
likewise, for the 10 Liters, if only 50% is salt, then is just (50/100) * 10 or 5.
now... let's check the water whilst we add "y" amount, the water has no salt at all, freshwater for that matter, so, salinity is 0%. or (0/100) * y or 0.