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Anuta_ua [19.1K]

4 years ago

6

How do I do this if carbon has 4 valence electrons and oxygen has six valance electrons how do I do that if they only need eight

valance electrons

1 answer:

Sveta_85 [38]4 years ago

4 0

The carbon will make two double bonds with the oxygen: O=C=O this way carbon will make 4 covalent bonds and oxygen will make 2 covalent bonds

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HELP ME, HOW? Draw on the graph a line that shows the car decelerating steadily to a stop from point D in 10 s. Mark the point w

Lady bird [3.3K]

Answer:

There is no deacceleration.

Explanation:

Let's check relation between velocity and acceleration

$\\ \rm\Rrightarrow a=\dfrac{dv}{dt}$

$\\ \rm\Rrightarrow a\propto dv$

So as velocity graph is going up acceleration is going up

Those flat lines on graph shows constant acceleration .

Curve lines up shows instantaneous acceleration.

If the graph is going down then it can be deacceleration .

Note :-No F is present in graph

5 0

2 years ago

Read 2 more answers

Mrac [35]

Answer:

1. Percent by mass of H₂O = 45.3%

2. Percent by mass of anhydrous Salt (FeSO₄) = 54.7 %

Explanation:

Data Given

Formula of the Molecule = FeSO₄ • 7H₂O

% by mass water (H₂O) = ?

% by mass FeSO₄ = ?

________________________________________

> First of all find the atomic masses of each component in a molecule

For H₂O atomic masses are given below

H = 1 g/mol

O = 16 g/mol

> Then find the total mass of H₂O in haydrated salt

7H₂O = 7 (2x1 +1x16) g/mol

7H₂O = 7 (2+16) g/mol

7H₂O = 7 (18) g/mol

7H₂O = 126 g/mol

> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = 278

Now to find the mass by percent of H₂O

Formula used to find the mass by percent of a component

Percent composition of H₂O = mass of H₂O in Molecule / molar mass of FeSO₄ • 7H₂O x 100%

Put the values

Percent by mass of H₂O = 126 (g/mol) / 278 (g/mol) x 100%

Percent by mass of H₂O = 0.4532 x 100%

Percent by mass of H₂O = 45.3%

_______________________________________________

> First of all find the atomic masses of each component in a molecule

For anhydrus salt (FeSO₄) atomic masses are given below

Fe = 56 g/mol

S= 32 g/mol

O = 16 g/mol

> Then find the total mass of FeSO₄ in haydrated salt

FeSO₄ = (56x1 + 32 + 4x16) g/mol

FeSO₄ = ( 56 + 32 + 64) g/mol

FeSO₄ = 152 g/mol

> find total Molar Mass of Molecule:

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 16x4] + 7(2+16)

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = [56+ 32 + 64] + 126

Molar Mass of FeSO₄ • 7H₂O = 278

Now to find the mass by percent of FeSO₄

Formula used to find the mass by percent of a component

Percent composition of FeSO₄ = mass of FeSO₄ in Molecule / molar mass of FeSO₄ • 7H₂O x 100%

Put the values

Percent by mass of FeSO₄ = 152 (g/mol) / 278 (g/mol) x 100%

Percent by mass of FeSO₄ = 0.547 x 100%

Percent by mass of FeSO₄ = 54.7 %

4 0

4 years ago

Read 2 more answers

Which is the electron configuration for boron?

Alexxx [7]

Boron:atomic number-5,valency-+3,atomic mass- 11amu

3 0

3 years ago

Read 2 more answers

QUESTION: A SCIENTIST NEEDS TO SEPARATE A MIXTURE OF SALT AND WATER. WHICH IF THE FOLLOWING

FromTheMoon [43]

Answer:

nosezjdkdodbdjdlhsjskdn

Explanation:

xdxdxdbzlxjdhfjfyufjfux

4 0

3 years ago

Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.

valina [46]

Answer: The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity = $4.184J/g^0C$

Initial temperature of the water = $T_i$ = 29.0°C

Final temperature of the water = $T_f$ = 46.0°C

Change in temperature , $\Delta T=T_f-T_i=(46.0-29.0)^0C=17.0^0C$

Putting in the values, we get:

$Q=7.40g\times 4.184J/g^0C\times 17.0^0C$

$Q=526J$

The amount of heat energy in joules required to raise the temperature is 526 Joules

4 0

3 years ago