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tatiyna
3 years ago
14

Plot the points (0, −3) and (−2,5) on the coordinate plane.

Mathematics
2 answers:
Gre4nikov [31]3 years ago
5 0
I hope this helps. ......,637363

strojnjashka [21]3 years ago
3 0
If you are asking how to plot the points then try this simple trick, a point is always (x,y) so the horizontal line of a graph will always be x and the vertical always y. So for your first point it says x=0 so place your finger on the 0 of the graph (in other words where the 4 lines meet) since it says y=-3 then you go down 3 spots. Your first point is graphed! Do you want to try finding the other point? I'll be here to help :)

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Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

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                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

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