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coldgirl [10]
3 years ago
15

Point w is on line segment VX. Given vx=4x, vw=3x and wx=5 determine the numerical length of vx

Mathematics
1 answer:
Viktor [21]3 years ago
6 0

Answer:

Numerical length of VX = 20

Step-by-step explanation:

Given that VX is a line segment which has a point W on it.

Kindly refer to the attached diagram for the given points.

We are also given the following dimensions:

VX=4x\\VW=3x\ and \\WX=5

To find:

Numerical length of VX = ?

Solution:

As we can clearly see from the attached diagram:

VX = VW + WX

Putting the given values:

4x=3x+5

Now, let us solve for x and then will put the value of x back to find the numerical value of VX.

\Rightarrow 4x-3x=5\\\Rightarrow x =5

Now,

VX = 4 \times x = 4\times 5 =\bold{20}

Therefore, numerical value of VX is <em>20</em>.

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The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485. For each decrease in unit p
Julli [10]

Answer:

a) Demand equation :y=-\frac{2}{25}x+725

b) Supply equation : y=\frac{7}{100}x+350

C) The equilibrium quantity and the equilibrium price are 2500 and $ 525 respectively

Step-by-step explanation:

We are given that  For each decrease in unit price of $20 below $485, the quantity demanded increases by 250 units.

Since decrease in unit price of $20 increase demand by 250 units

So, Slope =\frac{-20}{250}=\frac{-2}{25}

We are given that The quantity demanded x of a certain brand of DVD player is 3000/week when the unit price p is $485.

Now for demand equation:

Use point slope form : y-y_1=m(x-x_1)

So, y-485=\frac{-2}{25}(x-3000)\\y=-\frac{2}{25}x+725

a)So, Demand equation : y=-\frac{2}{25}x+725

Now to find supply equation

We have two points (0,350) and (2500,525)

(x_1,y_1)=(0,350)\\(x_2,y_2)=(2500,525)\\y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\y-350=\frac{525-350}{2500-0}(x-0)\\y-350=\frac{7}{100}x\\y=\frac{7}{100}x+350

b) So, Supply equation : y=\frac{7}{100}x+350

Now to find equilibrium quantity and price equate demand and supply equation

-\frac{2}{25}x+725=\frac{7}{100}x+350\\725-350=\frac{7}{100}x+\frac{2}{25}x\\x=2500

So, equilibrium quantity = 2500

To find equilibrium price substitute equilibrium quantity in any equation

y=\frac{7}{100}x+350\\y=\frac{7}{100}(2500)+350\\y=525

C) The equilibrium quantity and the equilibrium price are 2500 and $ 525 respectively

4 0
4 years ago
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