3 years ago

I don't know the answer

1 answer:

8 0

Check the picture below

thus, use the pythagorean theorem to get "x"

$\bf c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite
\end{cases}$

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

64 divided by 6 with remainder

JulijaS [17]

Hey there

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is 10 with remainder 4
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6 0

3 years ago

The equation (m^5/6) (m^1/6) ^7 =m^x what is the value of x that makes the equation true?

Nitella [24]

Answer:

Step-by-step explanation:

We have the equation

$m^{5/6}(m^{1/6})^7=m^x$

The exponent rules to be used are

$a^x\times a^y=a^{x+y}$

$(a^{x})^y=a^{xy}$

$m^{5/6}(m)^{7/6}=m^x\\\Rightarrow m^{\dfrac{5}{6}+\dfrac{7}{6}}=m^x\\\Rightarrow m^{\dfrac{5+7}{6}}=m^x\\\Rightarrow m^{\dfrac{12}{6}}=m^x\\\Rightarrow m^{2}=m^x$

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