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Rus_ich [418]
3 years ago
11

Find the midpoint of the line segment with the endpoints (-6, -8) and (-2, -6)

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0
Answer:
(-4,-7)

Explanation:
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Simplify 12 + 16 ÷ 4 · 5 - 8​
elena55 [62]

Step-by-step explanation:

12 + 16 ÷ 4 × 5 - 8

12 + 4 × 5 - 8

12 + 20 - 8

32 - 8

24

7 0
3 years ago
Read 2 more answers
Find the domain and range of f(x)= 2|x+2|-8​
nordsb [41]

Answer:

Domain (-∞,∞)

Range: [-8,∞)

3 0
3 years ago
Determine if the table shows a linear or an exponential function​
____ [38]

Answer:

<em>The table shows an exponential function</em>

Step-by-step explanation:

<u>Linear vs Exponential Functions</u>

A linear function is written as:

y=mx+b

where m and b are constants.

If a table contains a linear function, then for each pair of ordered pairs (x1,y1) and (x2,y2), the value of m must be constant.

The slope can be calculated as:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

An exponential function is written as:

y=y_o.r^x

Where r is the ratio and yo is a constant.

If a table contains an exponential function, for two ordered pairs (x1,y1) and (x2,y2), the value of r must be constant.

The ratio can be calculated as:

\displaystyle r=\sqrt[x2-x1]{\frac{y2}{y1}}

Calculate the slope for (0,4) and (1,2):

\displaystyle m=\frac{2-4}{1-0}=-2

Calculate the slope for (1,2) and (2,1):

\displaystyle m=\frac{1-2}{2-1}=-1

Since the slope is not the same, the function is not linear.

Now calculate the ratio for (0,4) and (1,2)

\displaystyle r=\sqrt[1-0]{\frac{1}{2}}

The radical of index 1 is simply equal to its argument:

\displaystyle r=\frac{1}{2}

Now calculate the ratio for (0,4) and (2,1)

\displaystyle r=\sqrt[2-0]{\frac{1}{4}}

\displaystyle r=\sqrt{\frac{1}{4}}

\displaystyle r=\frac{1}{2}

Testing other points we'll find the same ratio, thus the table is an exponential function

4 0
3 years ago
Read 2 more answers
Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3
yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
2 years ago
What is the equation of the line that passes through the points (1, −10) and (−4, −7)?
nignag [31]

Hi there! :)

First, let's find the slope using this formula:

m=\frac{y2-y1}{x2-x1}

m=\frac{-7-(-10)}{-4-1} \\\frac{-7+10}{-5} \frac{3}{-5} =-\frac{3}{5}

Now, use the Point-Slope formula:

y-y1=m(x-x1)

y-(-10)=-3/5(x-1)

y+10=-3/5x+3/5

y=-3/5x+3/5-10

y=-3/5x-9.4

Hope this helps..

~Just an emotional teen who listens to "Try Everything"

SilentNature

4 0
2 years ago
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