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2 years ago

PLEASE HELP ASAP I'M BEING TIMED!!!!!!!!!!!!!!!!!!!!!! WIll mark BRAINLIEST!!!!!!!!!!!!

Mathematics

2 answers:

statuscvo [17]2 years ago

7 0

The answer is A) Use the distance formula to find the length of each side, and then add the lengths.

irina [24]2 years ago

6 0

A) Use the distance formula to find the length of each side, and then add the lengths.

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99.999 rounded to the nearest tenth would be?

ale4655 [162]

Answer:

Look at the place after the tenths, it is more than 5.

99.999

So add +1 to the tenths place.

Rounded to the nearest tenth would be:

4 0

3 years ago

Read 2 more answers

Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min

alina1380 [7]

Answer:

$y=\frac{1}{2}x-2$

Step-by-step explanation:

We have been given two points on a line $(-6,-5)$ and $(-4,-4)$ . We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation $y=mx+b$ , where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

Let point $(-6,-5)=(x_1,y_1)$ and point $(-4,-4)=(x_2,y_2)$ .

$m=\frac{-4-(-5)}{-4-(-6)}$

$m=\frac{-4+5}{-4+6}$

$m=\frac{1}{2}$

Now, we will substitute $m=\frac{1}{2}$ and coordinates of point $(-6,-5)$ in slope-intercept form of equation as:

$-5=\frac{1}{2}*(-6)+b$

$-5=-3+b$

$-5+3=-3+3+b$

$-2=b$

Upon substituting $m=\frac{1}{2}$ and $b=-2$ in slope-intercept form of equation, we will get our required equation as:

$y=\frac{1}{2}x-2$

Therefore, our required equation would be $y=\frac{1}{2}x-2$ .

8 0

2 years ago

Find the proper answer

Temka [501]

I think the answer is C

8 0

2 years ago

3x – 2y = 17 <br> –2x – 5y = 14 <br> Solve using Elimination Please show work

OleMash [197]

Answer:

The solution is x=3 , y=-4 or (3,-4)

Step-by-step explanation:

Given equations (1 and 2) are:

$3x- 2y = 17\\-2x -5y = 14$

To solve a system of equation with elimination method, the co-efficients of one of the variables has to be equated and then the equations are added or subtracted to get an equation in one variable.

Multiplying equation 1 by 2:

$2(3x-2y) = 2*17\\6x-4y = 34\ \ \ \ \ Eqn\ 3$

Multiplying equation 2 by 3

$3(-2x-5y) = 3*14\\-6x-15y = 42\ \ \ \ Eqn\ 4$

Adding equation 3 and 4

$(6x-4y) + (-6x-15y) = 34+42\\6x-4y-6x-15y = 76\\-19y = 76\\\frac{-19y}{-19} = \frac{76}{-19}\\y = -4\\$

Putting y = -4 in equation 1

$3x-2(-4) = 17\\3x+8 = 17\\3x = 17-8\\3x = 9\\\frac{3x}{3} = \frac{9}{3}\\x = 3$

Hence,

The solution is x=3 , y=-4 or (3,-4)

3 0

2 years ago

Can someone help? It’s about 2 column proofs

Gwar [14]

Step-by-step explanation:

1. AB = BC (B is the midpoint of AC)

2. DE = EF (E is the midpoint of DF)

3. EB is common

4. ∠ABE = ∠CBE; ∠BED = ∠BEF (EB⊥AC, EB⊥DF)

5. ΔDEB ≅ ΔFEB (RHS)

6. DB = FB (corresponding ∠s of ≅ Δs)

7. ∠EFB = ∠CBF; ∠EDB = ∠ABD (alternate interior angles, AC║DF)

8. ΔABD ≅ ΔCBF (SAS)

4 0

2 years ago