3 years ago

What is the slope of a line perpendicular to the line whose equation is 2x+8y -64 Fully reduce your answer.

1 answer:

6 0

Answer: I am pretty sure it is y=-1/4x-8. Hope this helps!

Step-by-step explanation:subtract the 2x from both sides which gives you 8y=-2x-64. Then you want to divide both sides by 8 to get y=-1/4x-8

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Answer:

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?

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