What is the slope of a line perpendicular to the line whose equation is 2x+8y -64 Fully reduce your answer.

1 answer:

6 0

Answer: I am pretty sure it is y=-1/4x-8. Hope this helps!

Step-by-step explanation:subtract the 2x from both sides which gives you 8y=-2x-64. Then you want to divide both sides by 8 to get y=-1/4x-8

You might be interested in

Lunna [17]

Just multiply all of them and if you aren’t sure just search up how to find serfsce area

4 0

3 years ago

Olegator [25]

Answer is D {-8, -3, 5, 7 }

hope it helps

8 0

3 years ago

pshichka [43]

We cannot see the whole question

3 0

3 years ago

makvit [3.9K]

Answer:

Step-by-step explanation:

the displacement is zero

5 0

3 years ago

Setler [38]

The length is 8 and the width is 4

P = L + L + W + W
P = 8 + 8 + 4 + 4
P = 16 + 4 + 4
P = 16 + 8
P = 24

5 0

3 years ago