If you flip 11 coins, the probability of not getting all 11 tails is

Given the function h(x) = 3(5)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.

otez555 [7]

We can write the function in terms of y rather than h(x) so that:

y = 3 (5)^x

A. The rate of change is simply calculated as:

r = (y2 – y1) / (x2 – x1) where r stands for rate

Section A:

rA = [3 (5)^1 – 3 (5)^0] / (1 – 0)

rA = 12

Section B:

rB = [3 (5)^3 – 3 (5)^2] / (3 – 2)

rB = 300

B. We take the ratio of rB / rA:

rB/rA = 300 / 12

rB/rA = 25

So we see that the rate of change of section B is 25 times greater than A

7 0

3 years ago

What is the mean of this? 48, 12, 35, 57, 42, 15, 74, 29. <br>ILL GIVE U BRAINLYEST

BlackZzzverrR [31]

answer:

48 + 12 + 35 + 57 + 42 + 15 + 74 + 29 = 312

divide by number of numbers,

312 / 8 = 39

the mean is 39.

<em>if correct, please mark the brainliest :)</em>

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8 0

2 years ago

Algebra problem below.

umka21 [38]

$A= \frac{1}{2}bh= \frac{1}{2}*18*11=9*11=99 \ ft^2$

3 0

3 years ago

A resercher is wondering whehter the drinking habits of adults in a certain region of the country are in the same proportion as

Andrews [41]

Answer:

Answer for the question :

A resercher is wondering whehter the drinking habits of adults in a certain region of the country are in the same proportion as the general population of adults. Suppose a recent study stated that the proportion of adults who reported drinking once a week or less in the last month was 0.26. The researcher's null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha; P> 0.26. The researcher collected datat from a random sample of 75 adults in the region of interest.

1- Verify that the normality assumption is satisfied. Describe each separately.

2- To cotinue the study into the drinking habits of adults, the researcher decides to collect datat from adults working in "blue collar" jobs to see whether their drinking habits are in the same proportion as the general public. The null hypothesis for this test is H0: P=0.26 and the alternative hypothesis is Ha: P>0.26. The researcher computer the test statistic to be 1.59. Draw a graph of z distribution, label the test statistic and shade the p-value associated with this test statistic."

is given in the attachment.

Step-by-step explanation:

3 0

3 years ago

In a set of integers from 140 to 200 inclusive, how many integers are divisible by 4 and 6?

Ronch [10]

The answer to the question asked is 5.

The least common multiple of 4 and 6 is 12. In the range 140 to 200, there are

... floor(200/12) - ceiling(140/12) + 1 = 16 - 12 + 1 = 5

integers divisible by 12.

_____

The list of answer choices suggests that the question is intended to be, "how many integers are divisible by 4 or 6?"

The number divisible by 4 is

... floor(200/4) - ceiling(140/4) + 1 = 50 - 35 + 1 = 16

The number divisible by 6 is

... floor(200/6) - ceiling(140/6) + 1 = 33 - 24 + 1 = 10

We know from the above that there are 5 values that are divisible by both 4 and 6, so will be counted twice if we simply add the above numbers. Hence the number of values divisible by 4 or 6 is

... 16 + 10 - 5 = 21 . . . . . corresponds to selection C)

3 0

3 years ago