What is the square root of 5?
2 answers:
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We were given the points, A(5,-3) and the midpoint of AB, M(-4,2).
Let point B have coordinates (c , d).
Then the midpoint of A(5, -3) and B(c,d)
Now let us compare to the given midpoint M(-4, 2).
We can then write the following equations for the corresponding coordinates.
Comparing x coordinates, we have;
Multiplying both sides of the equation by 2 gives,
5+c = 2(-4)
Simplifying the right hand side gives,
5 + c = -8
Grouping like terms, we have,
c = -8 - 5
This simplifies to,
c = -13
Comparing y coordinates we have,
Multiplying through by 2 gives,
-3 + d = 2(2)
This means that,
-3 + d = 4
Making the subject we have,
d = 4+3
This implies that,
d = 7
Hence the coordinates of B are (-13,7).
Let point B have coordinates (c , d).
Then the midpoint of A(5, -3) and B(c,d)
Now let us compare to the given midpoint M(-4, 2).
We can then write the following equations for the corresponding coordinates.
Comparing x coordinates, we have;
Multiplying both sides of the equation by 2 gives,
5+c = 2(-4)
Simplifying the right hand side gives,
5 + c = -8
Grouping like terms, we have,
c = -8 - 5
This simplifies to,
c = -13
Comparing y coordinates we have,
Multiplying through by 2 gives,
-3 + d = 2(2)
This means that,
-3 + d = 4
Making the subject we have,
d = 4+3
This implies that,
d = 7
Hence the coordinates of B are (-13,7).
This equation is in slope-intercept form: y = mx + b, where m is the slope, and b is the y-intercept.
To find the slope of y = - 8 x - 3, we have to find what replaced m. -8 replaced m here, so -8 is the slope of this equation.