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astra-53 [7]
2 years ago
14

Which equation can be used to find the solution of (1/3)^d−5=81 ?

Mathematics
1 answer:
horsena [70]2 years ago
4 0

Let's solve your equation step-by-step.

Step 1: Add 5 to both sides.

\frac{1}{3}^{2} -5+5=81+5

\frac{1}{3}^d =86

Step 2: Solve Exponent to get.

d = −4.054522   or -4.05  hope this helps


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Answer:

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Step-by-step explanation:

The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.

That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.

If k is subtracted, instead of added, then the point will be moved downward.

The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.

_____

<em>Comment on the question</em>

The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.

If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.

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3 years ago
Greatest to least - 1/2, 3/5, 3/7
Natalka [10]
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An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

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