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olga nikolaevna [1]
3 years ago
9

Which equation represents a circle with the same radius as the circle shown but with a center at (-1,1)

Mathematics
2 answers:
Alex_Xolod [135]3 years ago
3 0

Answer:

(x + 1)² + (y - 1)² = 16

Step-by-step explanation:

Since the standard form for an equation of a circle is

<h3> (x - h)² + (y - k)² = r²</h3>

The (h,k) are co-ordinate of your centre of circle, which in this case is (-1,1) and r is the radius of circle.

As we can see in the figure radius = 4units

<em>from centre(1,-2) to (1,-2)</em>

Put these into the equation

(x + 1)² + (y - 1)² = 4²

(x + 1)² + (y - 1)² = 16

ella [17]3 years ago
3 0

Answer:

The equation of the circle is:

              (x+1)^2+(y-1)^2=4^2

                           or

                x^2+y^2+2x-2y=14

Step-by-step explanation:

The radius of the given circle as represented in the graph is: 4 units.

The center of a circle is: (-1,1)

We know that the equation of a circle with center (h,k) and radius r is given by:

(x-h)^2+(y-k)^2=r^2

We have:

r=4 and (h,k)=(-1,1)

Hence, the equation of circle is:

(x+1)^2+(y-1)^2=4^2\\\\\\x^2+1+2x+y^2+1-2y=16\\\\x^2+y^2+2x-2y=14

              Hence, equation is:

            (x+1)^2+(y-1)^2=4^2

                           or

                x^2+y^2+2x-2y=14

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