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Nata [24]
3 years ago
14

Which expression is equivalent to -8(5m - 7.4)?

Mathematics
2 answers:
atroni [7]3 years ago
8 0
I would said B !

Explanation: start with solving what’s in the parenthesis then multiply -8 which gives you the answer of 19.2 ! Then solve all your answer choices and find the one that matches and it was B .
IgorLugansk [536]3 years ago
3 0
B because you multiply -8*5m and then -8*-7.4 getting you -40+59.2
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If the scale factor is
klemol [59]

If the scale factor is 1/5, then the area of the preimage is multiplied by <u>0</u><u>.</u><u>2</u> or <u>1</u><u>/</u><u>5</u> to calculate the area of the new image.

6 0
2 years ago
8. Find GH,<br> E<br> 3-4<br> HY<br> -<br> H<br> 2<br> 3x - 4<br> G<br> SI<br> F<br> 9x - 59<br> D
Ostrovityanka [42]

Answer:

GH= 47

Step-by-step explanation:

2(3x - 4) = 9x - 59

6x - 8 = 9x - 59

6x - 9x =  - 59  + 9

\cfrac{ - 3x}{ - 3}  =  \cfrac{ - 51}{ - 3}

x = 17

gh = 3(17)  - 4

51 - 4

= 47

~

8 0
3 years ago
Explain how you would write 423,090,709,000 in word form
inessss [21]
In word form is: Four hundred twenty three billion, ninety million, seven hundred nine thousand.

4 0
3 years ago
Read 2 more answers
PLZ HELP ME! Whoever gets it right will be marked brainiest
Brut [27]

Answer:

Probability that Hannah only has to buy 3 or less boxes before getting a prize is 0.784

Step-by-step explanation:

Given, 40% of cereal boxes contain a prize

⇒probability of getting a prize on opening a box, P(A)=0.4

where A is the event of getting a prize on opening a cereal box

and probability of not getting a prize on opening a box, P(A')=1-P(A)=0.6

where A' is the event of not getting a prize on opening a cereal box

This problem needs to be divided into 3 situation:

  • Case 1, Where Hannah gets prize when she buys the first box:

Let K be the event of Hannah winning the prize on buying the first box.

⇒P(K)=P(A)=0.4

  • Case 2, Where Hannah gets prize when she buys the second box:

I<u>n this event Hannah should not get the prize in first box but should get the prize on buying the second box</u>

Let L be the event of Hannah winning the prize on buying the second box

So, P(L)=P(A')·P(A)

           =(0.6)·(0.4)

           =0.24

  • Case 3,Where Hannah gets prize when she buys the third box:

<u>In this event Hannah should not get the prize in first and second box but should get the prize on buying the third box</u>

Let L be the event of Hannah winning the prize on buying the third box

So, P(L)=P(A')·P(A')·P(A)

           =(0.6)·(0.6)·(0.4)

           =0.144

Let N be the event of Hannah winning the prize on buying 3 or less boxes before getting a prize

⇒N=K∪L∪M

Now, Required probability is P(N)=P(K∪L∪M)=P(K)+P(L)+P(M) [As events K,L and M are independent and disjoint events]

⇒P(N)=0.4+0.24+0.144

         =0.784

7 0
3 years ago
Diagram shows two perpendicular straight lines,OB and CBD,drawn on a Cartesian plane.
Tems11 [23]

Answer: (a) y = -3x + 10

               \bold{(b)\x=\bigg(\dfrac{10}{3},0\bigg)}  

<u>Step-by-step explanation:</u>

The slope of line CD is perpendicular to line OB, which means they have opposite and reciprocal slopes.

Step 1: Find the slope of OB using the formula: m=\dfrac{y_2-y_1}{x_2-x_1}

(x₁, y₁) = (0, 0) and (x₂, y₂) = (3, 1)

m=\dfrac{1-0}{3-0} = \dfrac{1}{3}

Step 2: Find the slope of CD (opposite and reciprocal of OB)

m = \dfrac{1}{3}\qquad m_\perp=-\bigg(\dfrac{3}{1}\bigg) = -3

Step 3: Input the perpendicular slope and the slope into the Point-Slope formula: y - y₁ = m(x - x₁)

(x₁, y₁) = (3, 1) because it is the point the line will pass through

y - 1 = -3(x - 3)

y - 1 = -3x + 9      <em>distributed -3 into (x - 3)</em>

y      = -3x + 10    <em>added 1 to both sides</em>

***********************************************************************

The x-intercept of DQ is the same x-intercept as CD.  The x-intercept is when y = 0

y = -3x + 10

0 = -3x + 10

-10 = -3x       subtracted 10 from both sides

\dfrac{10}{3}=x    <em>divided both sides by -3</em>


3 0
3 years ago
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