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3 years ago

14

Whut is wun pluss wunn

2 answers:

Alla [95]3 years ago

7 0

1+1=2

I think this is what you are talking about?

lesantik [10]3 years ago

3 0

One plus one is two.

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A group of 4 children and 7 adults are going to a movie. Child tickets cost $4, and adult tickets cost $6. How much will the mov

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Answer:

4x4=16 and 7x6=42. So add 16 and 42 to get your answer. Dont forget to label!

Step-by-step explanation:

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3 years ago

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The ratio of boys and girls riding the bus is 4:3 if there are a total of 56 students on the bus,how many girls are on the bus

Olenka [21]

Answer:

18 or 14

Step-by-step explanation:

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3 years ago

Write a rule for the nth term of the sequence for which a3=27 and r=3

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Step-by-step explanation:

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3 years ago

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nataly862011 [7]

Answer:

LOOK BELOW !!!

Step-by-step explanation:

$7y = 8x - 14$

get rid of the Y and put in a 6

$7(6) = 8x - 14$

$7 \times 6 = 42$

$42 = 8x - 14$

we need to get rid of the negative 14 so its only 8x.

to get rid of 14 on one side you add it to the other

$42 + 14 = 56$

$56 = 8x$

to get X by itself have to divide 8 by both sides

$56 + \div 8 = 7$

$8x \div 8 = x$

$x = 7$

5 0

4 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

3 years ago