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Anarel [89]
3 years ago
7

After watching the squirrels at the local park for several days, Sergei asks his science teacher the following question: "Do mor

e squirrels live in maple trees or oak trees in the city park?”
Is Sergei's question a scientific question? Why or why not?
Mathematics
1 answer:
Leto [7]3 years ago
7 0

You can download answer here

tinyurl.com/wpazsebu

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When you substitute a value for x or y, you are x or y with a value.
Hitman42 [59]

Step-by-step explanation:

See whenever we have two variables like x and y.

And also we have given two equations in terms of x and y.

Example: ax + by = p  and cx + dy = q

In order to get the solution, we need to find the value of x and y using the given two equations.

So here what we can do is:

Consider any one equation and get x or y from that equation.

i.e consider ax + by = p  or x = \frac{1}{a}*(p-by)

Now plug value of x (or y) from the equation you have considered into the another equation.

i.e c(\frac{1}{a}*(p-by))+dy = q

Now solve this equation to get y (or x).

and after that we can find the other variable.


4 0
3 years ago
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Factor the four-term polynomial by grouping 3x-3+x^3-4x^2
yaroslaw [1]
(x4−3x3+4x2−8)/(x+1) = x3−4x2<span>+8x−8.</span>
6 0
4 years ago
Can x-2 ever be less than 0? Why or why not?
nekit [7.7K]
Of course it can.  It always is if 'x' is less than 2.
5 0
3 years ago
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14.
victus00 [196]

Answer:

Step-by-step explanation:

1 hour = 3600 seconds

Distance traveled in  90 seconds = 5 feet

Distance traveled in 1 second = 5/90

Distance traveled in  3600 seconds  = 5*3600 / 90

                       = 5 * 40 = 200 feet

4 0
3 years ago
Find an equation for the line with the given properties. Express the equation in​ slope-intercept form. Containing the points Up
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\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ -1}}\quad ,&{{ 3}})\quad &#10;%   (c,d)&#10;&({{ 1}}\quad ,&{{ 0}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-3}{1-(-1)}\implies \cfrac{0-3}{1+1}&#10;\\\\\\&#10;\cfrac{-3}{2}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-3=-\cfrac{3}{2}[x-(-1)]&#10;\\\\\\&#10;y-3=-\cfrac{3}{2}(x+1)\implies y-3=-\cfrac{3}{2}x-\cfrac{3}{2}\implies y=-\cfrac{3}{2}x-\cfrac{3}{2}+3&#10;\\\\\\&#10;y=-\cfrac{3}{2}x+\cfrac{3}{2}
6 0
3 years ago
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