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Anarel [89]
2 years ago
7

After watching the squirrels at the local park for several days, Sergei asks his science teacher the following question: "Do mor

e squirrels live in maple trees or oak trees in the city park?”
Is Sergei's question a scientific question? Why or why not?
Mathematics
1 answer:
Leto [7]2 years ago
7 0

You can download answer here

tinyurl.com/wpazsebu

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What is the twentieth term of the arithmetic sequence described by the<br> equation an= 3n - 10?
sergij07 [2.7K]

Answer:

The twentieth term is 50.

Step-by-step explanation:

The equation that describes the arithmetic sequence describes it's "general term", which means that all the numbers in that sequence must follow that equation. For instance, if we want to find the first term of the sequence we must make a = 1 and we have:

a1 = 3*1 - 10

a1 = -7

Therefore to find the twentieth term we need to make n equal to 20. This is done below:

a20 = 3*20 - 10

a20 = 60 - 10

a20 = 50

The twentieth term is 50.

8 0
3 years ago
You have 2/3 of sugar how muck sugar will you use if you makes 6 batches of cookies
zalisa [80]

Answer:

4

Step-by-step explanation:

1 batch = 2/3

so 6 batches = 2/3 * 6

and 2/3 *6 = 4 !

4 0
2 years ago
Plz plz help urgently ❤️
Delicious77 [7]

Answer:

D.

Step-by-step explanation:

5 0
3 years ago
Solve: 3n+18-n=38<br>Need help
docker41 [41]
Hope this helps you!

4 0
3 years ago
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
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