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docker41 [41]
3 years ago
8

Will mark as Brainliest.

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0
5/7 I the most likely 

in all/favroitable ammount
Inga [223]3 years ago
7 0
5/7 would be defective because 5 out of 7 of them dont work.
You might be interested in
The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is
liraira [26]

we know that

The LCD is the LCM (least common multiple) of all the denominators.

we have

1/3, 3/4, 5/32, 8/9

3=3^{1} \\ 4=2^{2} \\ 32=2^{5} \\ 9=3^{2}

LCM=2^{5} *3^{2} \\ LCM=32*9\\ LCM=288

So

The LCM of 3, 4, 32, 9 is 288 ,

which is the multiple of the highest power of prime factors from all of the given numbers

therefore

the answer is

288

8 0
3 years ago
Read 2 more answers
Find the slope of the line through the pair of points (-4,12) , (-4,11)
Hoochie [10]

Answer:

Pretty sure its undefined

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the value of the variable y, where the sum of the fractions 6/(y+1) and y/(y-2) is equal to their product.
Blizzard [7]

Answer:

The answer is

y = 3

y =  - 4

Step-by-step explanation:

We must find a solution where

\frac{6}{y + 1}  +  \frac{y}{y - 2}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Consider the Left Side:

First, to add fraction multiply each fraction on the left by it corresponding denomiator and we should get

\frac{6}{y + 1}  \times  \frac{y - 2}{y - 2}  +  \frac{y}{y - 2}  \times  \frac{y + 1}{y + 1}

Which equals

\frac{6y - 12}{(y -2) (y + 1)}  +  \frac{ {y}^{2} + y }{(y - 2)(y + 1)}

Add the fractions

\frac{y {}^{2} + 7y - 12 }{(y - 2)(y + 1)}  =  \frac{6}{y + 1}  \times  \frac{y}{y - 2}

Simplify the right side by multiplying the fraction

\frac{6y}{(y  + 1)(y + 2)}

Set both fractions equal to each other

\frac{6y}{(y + 1)(y - 2)}  =  \frac{ {y}^{2} + 7y - 12}{(y + 1)(y - 2)}

Since the denomiator are equal, we must set the numerator equal to each other

6y =  {y}^{2}  + 7y - 12

=  {y}^{2}  + y - 12

(y  + 4)(y - 3)

y =  - 4

y = 3

6 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 140 and the length is 10 more than four times the width. find the dimensions
aalyn [17]

Answer:

Width = 12

Length = 58

Step-by-step explanation:

Width = x

Length = 4x + 10

Perimeter = 140

2 * ( length + width )  = 140

2 * (4x +10 + x) = 140

            5x + 10 = 140/2 = 70

                     5x = 70- 10

                     5x = 60

                         x = 60/5 = 12

Width = 12

Length = 4 * 12 + 10 = 48 +10 = 58

7 0
3 years ago
Read 2 more answers
Among all pairs of numbers whose difference is 6, find a pair whose product is as small as possible. What is the minimum produc
mixas84 [53]

Answer:

pairs of numbers is 3,-3

Step-by-step explanation:

The computation is shown below:

Let us assume a and b are the pairs of the numbers whose difference is 6

i.e.

a - b = 6

a = 6 + b

So

f = ab

f = (6 + b)b is minimum

Now

d ÷ db (6+ b)b = 0

(6+ b) + b = 0

2b = -6

b = -3

Now

a  = 6 + b

= 3

So pairs of numbers is 3,-3

6 0
3 years ago
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