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Harrizon [31]
3 years ago
9

Among all pairs of numbers whose difference is 6, find a pair whose product is as small as possible. What is the minimum produc

The pair of numbers whose difference is 6 and whose product is as small as possible is ? ​
Mathematics
1 answer:
mixas84 [53]3 years ago
6 0

Answer:

pairs of numbers is 3,-3

Step-by-step explanation:

The computation is shown below:

Let us assume a and b are the pairs of the numbers whose difference is 6

i.e.

a - b = 6

a = 6 + b

So

f = ab

f = (6 + b)b is minimum

Now

d ÷ db (6+ b)b = 0

(6+ b) + b = 0

2b = -6

b = -3

Now

a  = 6 + b

= 3

So pairs of numbers is 3,-3

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3. Simplify -1+2 to 1

x > 1

The answer is x > 1.

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A.) 15.7in<br> B.) 31.4in<br> C.) 40in<br> D.) 62.8in
IrinaK [193]

Answer:

31.4 in

Step-by-step explanation:

This is a tricky question,

if you observe the shape carefully, you will notice that if you mirror (flip outward) each curve surface of each quardrant, what you will end up with is a complete circle with a radius of 5 inches.

Hence the combined length of all the curved surfaces is simply the circumference of the circle, given by:

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3 years ago
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Find a2 and a3 for the geometric sequence 4, a2, a3, 108.
LekaFEV [45]

9514 1404 393

Answer:

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Step-by-step explanation:

Terms of a geometric sequence have a common ratio. If we call that ratio r, then we have ...

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__

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3 years ago
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Step-by-step explanation:

The point-slope form of an equation of a line:

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y-1=\dfrac{1}{2}(x-(-2))

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Covert to the slope-intercept form (y = mx + b):

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-x+2y=4         <em>change the signs</em>

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Convert to the general form (Ax+By+C=0):

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