The answer is b) :) hope i helped!
Answer:
The range of the oven is 
Step-by-step explanation:
Consider the provided information.
The internal temperature falls to 20 degrees below the set temperature and turns off when the temperature reaches 5 degrees above the set temperature.
You preheat the oven to 405 degrees before putting a cake in and baking it for an hour at 405.
The internal temperature falls to 20 degrees, therefore the lowest set can be:
405-20=385 degree.
The temperature reaches 5 degrees above the set temperature 405, therefore the upper set is: 405+5=410 degree.
Hence, the temperature will be lying between 385 degree and 410 degree.
This can be written as:
Hence, the range of the oven is
Solve your equation step-by-step.
x^2+5=41
Subtract 5 from both sides.
x^2+5−5=41−5
x^2=36
Take square root.
x=±√36
x=6
or
x=−6
So your answer suppose to be C and D.
But if you were to put only one answer in the answering box, then just say C)
Answer: Isolate the variable by dividing each side by factors that don't contain the variable. x=−1/2^2
Step-by-step explanation:
Answer:
1. g. $0.10 per square inch
2. c. $0.08 per square inch
3. f. $10
4. m. $8
5. h. 79 in²
6. j. 113 in²
Step-by-step explanation:
1. A = πr²
r = diameter ÷ 2 = 10 ÷ 2 = 5
A = π(5)² = 25π in² ≈ 78.53981
$8.00/25π = $0.10 per square inch
2. A = πr²
r = diameter ÷ 2 = 12 ÷ 2 = 6
A = π(6)² = 36π in² ≈ 113.0973355
$10.00/36π = 0.088419 = $0.08 per square inch
3. information/answer was provided
4. information/answer was provided
5. A = πr²
r = diameter ÷ 2 = 10 ÷ 2 = 5
A = π(5)² = 25π in² ≈ 79 in²
6. A = πr²
r = diameter ÷ 2 = 12 ÷ 2 = 6
A = π(6)² = 36π in² ≈ 113 in²
