25, and 12.5... it is dividing by a half each time, so half of 50 is 25 and half of 25 is 12.5, hope this helps!
Answer:
A. v = 19√3.
B. u = 38.
Step-by-step explanation:
The following data were obtained from the question:
Angle θ = 60°
Adjacent = 19
Opposite = v
Hypothenus = u
A. Determination of the value of 'v'
The value of v can be obtained by using Tan ratio as shown below:
Angle θ = 60°
Adjacent = 19
Opposite = v
Tan θ = Opposite /Adjacent
Tan 60 = v/19
Cross multiply
v = 19 × Tan 60
Tan 60 = √3
v = 19 × √3
v = 19√3
Therefore, the value of v is 19√3
B. Determination of the value of 'u'
The value of u can be obtained by using cosine ratio as shown below:
Angle θ = 60°
Adjacent = 19
Hypothenus = u
Cos θ = Adjacent /Hypothenus
Cos 60 = 19/u
Cos 60 = 1/2
1/2 = 19/u
Cross multiply
u = 2 × 19
u = 38
Therefore, the value of u is 38.
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Answer:
0.5 = 50% probability a value selected at random from this distribution is greater than 23
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability a value selected at random from this distribution is greater than 23?
This is 1 subtracted by the pvalue of Z when X = 23. So
has a pvalue of 0.5
0.5 = 50% probability a value selected at random from this distribution is greater than 23
Answer:
If I'm correct, the answer should be negative 40/3.
Step-by-step explanation:
Because you first combine multiplied terms into a single fraction, then you multiply all terms by the same value to eliminate fraction denominators. Now you simplify it, by canceling multiplied terms that are in the denominator and then you multiply the numbers. Now you will divide both sides of the equation by the same term. Finally, you will simplify the equation.
(Hope this helps) I had to get a little help myself on this problem)
