We will have that for the previous year, he had in the account:
For the year previous to that one, he had:
For the previous year to that, he had:
For the year previous to that one, he had:
For the second year that the money was in the account, there was:
And the orinial ammount of money that was in the account was:
From this, we know that Jhon had originally $1400.37 in the bank account.
Answer:
71100139<u>2</u>
321000<u>7</u>59
Step-by-step explanation:
hope it helps ^o^
Asking the Math Gods...
The factors of 15 Answer : 1,3,5,15
so 3 and 5 are the only that would get 15
therefore this problem isnt correctly written.. You can't get 6 by adding any of the factored numbers
Answer:
the solution is x = 2 and y = 4 OR (2,4)
Step-by-step explanation:
From the question
Equation 1: 3x-2y= -2
Equation 2: 3x + y = 10
Subtract equation 1 from equation 2, that is
3x + y = 10 - (3x -2y = -2)
You get
3x - 3x + y - (-2y) = 10 - (-2)
0 + y + 2y = 10 + 2
3y = 12
Divide both sides by 3
∴ y = 12/3
y = 4
Substitute the value of y into equation 2 to get x
3x + y = 10
3x + 4 = 10
Then,
3x = 10 - 4
3x = 6
Divide both sides by 3
∴ x = 6/3
x = 2
Hence, the solution is x = 2 and y = 4
