Answer:
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Answer:
what problem?
Step-by-step explanation:
Answer:y= -4
Step-by-step explanation:
1 Solve for xx in 7x-4y=-127x−4y=−12.
x=\frac{4(y-3)}{7}
x=
7
4(y−3)
2 Substitute x=\frac{4(y-3)}{7}x=
7
4(y−3)
into 9x-4y=-209x−4y=−20.
\frac{36(y-3)}{7}-4y=-20
7
36(y−3)
−4y=−20
3 Solve for yy in \frac{36(y-3)}{7}-4y=-20
7
36(y−3)
−4y=−20.
y=-4
y=−4
4 Substitute y=-4y=−4 into x=\frac{4(y-3)}{7}x=
7
4(y−3)
.
x=-4
x=−4
5 Therefore,
\begin{aligned}&x=-4\\&y=-4\end{aligned}
x=−4
y=−4
5*2x is 10x
5*3y is 15y
5*5z is 25z
Answer:
The solution of the given initial value problems in explicit form is
and the solutions are defined for all real numbers.
Step-by-step explanation:
The given differential equation is

It can be written as

Use variable separable method to solve this differential equation.

Integrate both the sides.

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... (1)
It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.



The value of C is -2. Substitute C=-2 in equation (1).
Therefore the solution of the given initial value problems in explicit form is
.
The solution is quadratic function, so it is defined for all real values.
Therefore the solutions are defined for all real numbers.