1 is in the one-tenths place. If 2 was in this spot, it would be two-tenths.

Here are the place values for the question's given number of 56.123.

5- tens
6- ones
decimal
1- tenths
2- hundredths
3- thousandths

ANSWER:
1 has the place value of C) one-tenth

Hope this helps! :)

6 0

3 years ago

Read 2 more answers

Latrell took one of his friends out to lunch. The lunches cost $60 and he paid 5% sales tax. If Latrell left a 15% tip on the $6

VladimirAG [237]

Answer:

$72

Step-by-step explanation:

Cost of the lunch = $60

Sales tax = 5% of $60

= 5/100 × 60

= 0.05 × 60

= $3

Tip = 15% of $60

= 15/100 × 60

= 0.15 × 60

= $9

how much in total did he pay?

Total amount paid = cost of the lunch + sales tax + tip

= $60 + $3 + $9

= $72

Latrell paid $72 in total for the lunch

4 0

3 years ago

Which of the following is an improper integral?

guapka [62]

Answer:

A) $\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx$

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

Removable (Hole)
Jump
Infinite (Asymptote)

Integration

Integrals
Definite Integrals
Integration Constant C
Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A) $\displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx$

B) $\displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx$

C) $\displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx$

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

6 0

3 years ago

simplify the expression below. Express the simplified expression in standard form (12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)

joja [24]

<h3>Answer: 14s^4 - 7s^2 + 15</h3>

====================================================

Work Shown:

(12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)

12s^4-6s^2+4s+6s^4-4s+27-4s^4-s^2-12

(12s^4+6s^4-4s^4)+(-6s^2-s^2)+(4s-4s)+(27-12)

14s^4-7s^2+0s+15

14s^4-7s^2+15

Note: don't forget to distribute the negative to every term in the last parenthesis

3 0

3 years ago