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3 years ago

Find the value of a if the line joining the points (3a,4) and (a,-3) has a gradient of 1

1 answer:

6 0

Recall that the slope or gradient of a line segment through two points is the ratio of the change in the y coordinate to the change in the x coordinate.

If the gradient is 1, then

1 = (-3 - 4) / (a - 3a)

Solve for a :

1 = -7 / (-2a)

1 = 7/(2a)

2a = 7

a = 7/2

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Eric made a scale drawing of the middle school. The scale he used was 1inch=5feet. If the gym is 30 inches by 20 inches in the d

BabaBlast [244]

Answer: 150 feet : 100 feet

Step-by-step explanation:

From the question, we are informed that the scale used by Eric was 1inch=5feet.

If the gym is 30 inches by 20 inches in the drawing, the acual length and width of the gym would be:

Length = 30 inches = 30 × 5 feet = 150 feet

Width = 20 inches = 20 × 5 feet = 100 feet

Therefore, the acual length and width of the gym would be 150 feet by 100 feet

6 0

3 years ago

Read 2 more answers

-3q + 12 greater than equal too 4q - 30 solve for q

valentina_108 [34]

Solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Step-by-step explanation:

We need to solve the inequality: $-3q+12\geq 4q-30$ and find value of q

Solving:

$-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6$

So, solving the inequality $-3q+12\geq 4q-30$ the value of q is $q\leq 6$

Keywords: Solving inequality

Learn more about solving inequality at:

#learnwithBrainly

6 0

3 years ago

Determine if the two triangles are congruent if so is it SSS,ASA,SAS,AAS

jonny [76]

Step-by-step explanation:

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2 years ago

In parallelogram DEFG, DH equals X +3, HF equals 3Y, GH equals 2X -5 and HE equals 5Y plus to find the values of X and Y

daser333 [38]

The values of X and Y are 30 and 11 respectively

<h3>How to determine the values of X and Y?</h3>

The figure that represents the complete question is added as an attachment

The given parameters are:

DH = X +3

HF = 3Y

GH = 2X -5

HE = 5Y

From the attached parallelogram, we have:

DH = HF

GH = HE

Substitute the known values in the above equation

X + 3 = 3Y

2X - 5 = 5Y

Make X the subject in X + 3 = 3Y

X = 3Y - 3

Substitute X = 3Y - 3 in 2X - 5 = 5Y

2(3Y - 3) - 5 = 5Y

Expand

6Y - 6 - 5 = 5Y

Evaluate the like terms

Y = 11

Substitute Y = 11 in X = 3Y - 3

X = 3*11 - 3

Evaluate

X = 30

Hence, the values of X and Y are 30 and 11 respectively