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labwork [276]
3 years ago
8

100 Points PLEASE ANSWER ASP! Will Give BRAINLIST!

Mathematics
2 answers:
VikaD [51]3 years ago
4 0

Let's work to solve this system of equations:

y = 2x ~~~~~~~~\gray{\text{Equation 1}}y=2x        Equation 1

x + y = 24 ~~~~~~~~\gray{\text{Equation 2}}x+y=24        Equation 2

The tricky thing is that there are two variables, xx and yy. If only we could get rid of one of the variables...

Here's an idea! Equation 11 tells us that \goldD{2x}2x and \goldD yy are equal. So let's plug in \goldD{2x}2x for \goldD yy in Equation 22 to get rid of the yy variable in that equation:

\begin{aligned} x + \goldD y &= 24 &\gray{\text{Equation 2}} \\\\ x + \goldD{2x} &= 24 &\gray{\text{Substitute 2x for y}}\end{aligned}  

x+y

x+2x

​    

=24

=24

​    

Equation 2

Substitute 2x for y

​  

Brilliant! Now we have an equation with just the xx variable that we know how to solve:

x+2x3x 3x3x=24=24=243=8Divide each side by 3

Nice! So we know that xx equals 88. But remember that we are looking for an ordered pair. We need a yy value as well. Let's use the first equation to find yy when xx equals 88:

\begin{aligned} y &= 2\blueD x &\gray{\text{Equation 1}} \\\\ y &= 2(\blueD8) &\gray{\text{Substitute 8 for x}}\\\\ \greenD y &\greenD= \greenD{16}\end{aligned}  

y

y

y

​    

=2x

=2(8)

=16

​    

Equation 1

Substitute 8 for x

​  

Sweet! So the solution to the system of equations is (\blueD8, \greenD{16})(8,16). It's always a good idea to check the solution back in the original equations just to be sure.

Let's check the first equation:

\begin{aligned} y &= 2x \\\\ \greenD{16} &\stackrel?= 2(\blueD{8}) &\gray{\text{Plug in x = 8 and y = 16}}\\\\ 16 &= 16 &\gray{\text{Yes!}}\end{aligned}  

y

16

16

​    

=2x

=

?

2(8)

=16

​    

Plug in x = 8 and y = 16

Yes!

​  

Let's check the second equation:

\begin{aligned} x +y &= 24 \\\\ \blueD{8} + \greenD{16} &\stackrel?= 24 &\gray{\text{Plug in x = 8 and y = 16}}\\\\ 24 &= 24 &\gray{\text{Yes!}}\end{aligned}  

x+y

8+16

24

​    

=24

=

?

24

=24

​    

Plug in x = 8 and y = 16

Yes!

​  

Great! (\blueD8, \greenD{16})(8,16) is indeed a solution. We must not have made any mistakes.

Your turn to solve a system of equations using substitution.

Use substitution to solve the following system of equations.

4x + y = 284x+y=28

y = 3xy=3x

LiRa [457]3 years ago
4 0

Answer:

1. Infinite Solutions.

2. a = 5, b = 2.

Step-by-step explanation:

1.  y = x + 5

4x - 4y = -20

Substitute y = x + 5 in the second equation:

4x - 4(x + 5) = -20

4x - 4x - 20 = -20

-20 = -20

The 2 equations are basically the same so we could enter any value of x and y we like and the equations would balance. Therefore:

There are infinite solutions.

2.  2a  = 6b - 2

2a + 3b = 16

From the second equation

2a = -3b + 16

So combining this with the first equation:

6b - 2 = -3b + 16    ( because both expressions are equal to 2a)

6b + 3b = 16 + 2

9b = 18

b = 2.

To find a substitute b = 2 into the first equation:

2a =  6(2) - 2

2a = 10

a = 5.

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Answer:

y= -2x+15

Step-by-step explanation:

5 0
2 years ago
HELP PLEASE DUE TODAY
N76 [4]

1 A. 5

1 B. 12.9

2. For this one, u can write any number less than 4.7, which could be 3, 2, -100, 1.21, etc.

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hope this helps!

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2 years ago
Which multiplication expression is eqeul to 3/5 ÷ 1/2
eduard

Answer:

Lets solve = 3/5 ÷ 1/2

3/5 ÷ 1/2

= 3/5 × 2/1

= 3 × 2/5 × 1

= 6/5

In mixed fraction its

1 \frac{1}{5}

____________________

Now lets solve "a" option

3/5 × 2

= 3 × 2/5 × 1

= 6/5

In mixed fraction

1 \frac{1}{5}

So option a = 3/5 x 2/1 is ur answer

8 0
2 years ago
Read 2 more answers
The sum of 3 consecutive integers is 27 less than the least of the integers..
zysi [14]

Answer:  -13, -15

Step-by-step explanation:

If x is the smallest integer, then:

x + (x + 1) + (x + 2) = x - 27

3x + 3 = x - 27

2x = -30

x = -15

Integers: -15, -14, -13

5 0
1 year ago
Anyone know the answer?
sdas [7]

Answer:

17

Step-by-step explanation:

14+3 it asked for total yards traveled

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