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mylen [45]
3 years ago
9

What happens to the Law of Cosines if the known angle is 90 degrees?

Mathematics
1 answer:
poizon [28]3 years ago
8 0

Answer:

See below.

Step-by-step explanation:

It transforms  to the Pythagoras theorem.

c^2  = a^2 + b^2 - 2ab cos C

If C = 90,  cos C = zero so the last term disappears.

c^2  = a^2 + b^2 - 2ab * 0

c^2 = a^2 + b^2.

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HEEEEEELP !
iogann1982 [59]

If you meant to write y=23x-4 then none of the lines are perpendicular.

I suspect you intended y=2/3x-4, then line D, y=-3/2x-4 is perpendicular.

For any line y=mx+b, you have to "invert" m to get  a perpendicular line. Inverting in this case means: flip numerator and denominator and add a minus sign.

So 2/3 becomes -3/2, hence answer D.

The 'inverted' m is called the opposite reciprocal. That's your word of the day.


6 0
3 years ago
a store buys a jacket for$20.00 and then sells it for 80% more what is the selling price for the jacket
victus00 [196]
Answer: 100$.

100% - 80% = 20%

20$ / 0.20(20%) =100$
7 0
3 years ago
What is the slope intercept form of the equation 4x-8y=72
Masteriza [31]

Answer:

y = 1/2x - 9

General Formulas and Concepts:

<u>Alg I</u>

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Standard Form: 4x - 8y = 72

<u>Step 2: Find slope-intercept form</u>

  1. Subtract 4x on both sides:          -8y = 72 - 4x
  2. Divide both sides by -8:               y = -9 + 1/2x
  3. Rewrite:                                         y = 1/2x - 9
6 0
2 years ago
Use U = {1,2,3,4,5,6,7,8,9,10}, A = {2,4,5}, B = {5,7,8,9}, and C = {1,3,10} to find the given set. AUB A. AUB = B. the solution
vesna_86 [32]

Answer:B

Step-by-step explanation:

3 0
3 years ago
Find all polar coordinates of point p where p = (6, -pi/5)
Lelu [443]
Given a point in coordinates form (r,\theta), one can compute the cartesian form like this:
(r\cos\theta,r\sin\theta )
We have:
r=6,\theta=-\dfrac{\pi}{5}
We get the cartesian form then:
\left(6\cos-\dfrac{\pi}{5},6\sin-\dfrac{\pi}{5}\right)
4 0
3 years ago
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