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Nadusha1986 [10]
3 years ago
7

How would you solve (4k+5)(k+1)=0?

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0
(4k+5)(k+1)=0\iff4k+5=0\ or\ k+1=0\\\\4k=-5\ or\ k=-1\\\\\boxed{k=-\frac{5}{4}\ or\ k=-1}
Kazeer [188]3 years ago
3 0
<span>(4k + 5) (k + 1) = 0

Before you rush off and start trying to do complicated things with that equation,
put your pencil down, fold your hands in your lap, and sit and look at it for a while.
Keep looking at it until a little voice yells out "Hey !  That's a true statement if
either </span><span>(4k + 5) is zero  or  </span><span><span>(k+1) is zero.  THEN go to work on it.

(4k + 5 = 0)
4k = -5
<u>k = -5/4</u>

(k + 1 = 0)
<u>k = -1</u>

And there are the two solutions to that equation.
</span></span>
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The width of a rectangular table is 2.3 feet less than its length. If the area of the table is 9.5 square​ feet, find its dimens
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If students’ scores were normally distributed and the mean was 200 with a standard deviation of 40, then what is the probability
Sonja [21]

Answer:

  84%

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The empirical rule tells you that 68% of the standard normal distribution is within 1 standard deviation of the mean. The distribution is symmetrical, so the amount in the lower tail is (1 -68%)/2 = 16%.

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4 0
3 years ago
Write an equation of the line passing through the point (3, -1) and parallel to the line y=2/3x - 5. Show work
alex41 [277]

Answer:

The answer is: y = 2/3x - 3

Step-by-step explanation:

Given point: (3, -1)

Given equation: y = 2/3x - 5, which is in the form y = mx + b where m is the slope and b is the y intercept.

Parallel lines have the same slope. Use the point slope form of the equation with the point (3, -1) and substitute:

y - y1 = m(x - x1)

y - (-1) = 2/3(x - 3)

y + 1 = 2/3x - 6/3

y + 1 = 2/3x - 2

y = 2/3x - 3

Proof:

f(3) = 2/3(3) - 3

= 6/3 - 3

= 2 - 3

= -1, giving the point (3, -1)

Hope this helps! Have an Awesome Day!!  :-)

6 0
3 years ago
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