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Nadusha1986 [10]
3 years ago
7

How would you solve (4k+5)(k+1)=0?

Mathematics
2 answers:
alukav5142 [94]3 years ago
5 0
(4k+5)(k+1)=0\iff4k+5=0\ or\ k+1=0\\\\4k=-5\ or\ k=-1\\\\\boxed{k=-\frac{5}{4}\ or\ k=-1}
Kazeer [188]3 years ago
3 0
<span>(4k + 5) (k + 1) = 0

Before you rush off and start trying to do complicated things with that equation,
put your pencil down, fold your hands in your lap, and sit and look at it for a while.
Keep looking at it until a little voice yells out "Hey !  That's a true statement if
either </span><span>(4k + 5) is zero  or  </span><span><span>(k+1) is zero.  THEN go to work on it.

(4k + 5 = 0)
4k = -5
<u>k = -5/4</u>

(k + 1 = 0)
<u>k = -1</u>

And there are the two solutions to that equation.
</span></span>
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

This is an example of a simultaneous equation.

First write this word problem as equations, where x is the "first number" that you've mentioned and y is the "second number".

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This is solved using the elimination method.

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Now subtract equation 1 from equation 2.

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amm1812
The answer to your problem is 6
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