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Lelu [443]
2 years ago
12

How many triangles can be formed with segments measuring 4. 7 m, 1. 6 m, and 2. 9 m? none one more than one.

Mathematics
1 answer:
Svet_ta [14]2 years ago
4 0

The sum of the length of the two sides of the triangle must be greater than the length of the third side. None of the triangles is formed. Then option A is correct.

<h3>What is the triangle?</h3>

Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.

The sides of the triangle are 4.7 m, 1.6 m, and 2.9 m.

The condition will be

1.6 + 2.9 \ngtr  4.7

We know that the sum of the length of two sides of the triangle must be greater than the length of the third side.

Hence, none of the triangles is formed.

Thus, option A is correct.

More about the triangle link is given below.

brainly.com/question/25813512

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Step-by-step explanation:

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Ricky is playing a racing game on PS5.
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
How do you write y=-4x^2-16x-14 in vertex form??
GREYUIT [131]

y= -4x² - 16x - 14


Take the coefficient of x² as the common factor

y = - 4(x² + 4x + 7/2)


Add (b/2)² to complete the square

y = - 4( x² + 4x + 2² - 2² + 7/2)


Complete the square

y = -4( (x + 2)² - 1/2)


Remove the bracket

y = -4(x + 2)² + 2


Answer: y = -4(x + 2)² + 2

8 0
3 years ago
Read 2 more answers
State whether the triangles could be proven congruent, if possible, by SSS or SAS.
Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0
3 years ago
A spinner for a board game consists of a cardboard circle with two plastic arrows anchored to its center. The arrows are congrue
tekilochka [14]

Answer:

Option (c) is correct.

The approximate total area of the plastic triangles on the spinner is 2 × 3.9 square centimeters = 7.7 square centimeters


Step-by-step explanation:

Given:A spinner for a board game consists of a cardboard circle with two plastic arrows anchored to its center. The arrows are congruent isosceles triangles connected at their bases.

also,  Given: The base of each triangle measures 2 centimeters and the perimeter of each triangle is 10 centimeters.

We have to find the approximate total area of the plastic triangles on the spinner.

Perimeter of triangle is the sum of sides.

Since given the triangle to be isosceles .

Let the two equal side be x cm, then,

Perimeter of given triangle = 1 0

⇒ x  + x + 2 = 1 0

⇒ 2x = 8

⇒ x = 4

Thus, side of triangle is 4 cm.

Now we find the area of  isosceles triangle.

We first find the height, using Pythagoras theorem,

(AC)^2=(AD)^2+(DC)^2

Putting values, we get,

(4)^2=(AD)^2+(1)^2

Solving we get,

AD=3.87

Thus, area of one isosceles triangle  A=\frac{1}{2} bh

area of one isosceles triangle  A=\frac{1}{2} \times 2 \times 3.87

On solving we get,

Approximate area of one plastic triangles on the spinner is 3.9 square centimeters.

Thus, the approximate total area of the plastic triangles on the spinner is 2 × 3.9 square centimeters = 7.7 square centimeters

Option (c) is correct.




7 0
3 years ago
Read 2 more answers
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