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Lelu [443]
2 years ago
12

How many triangles can be formed with segments measuring 4. 7 m, 1. 6 m, and 2. 9 m? none one more than one.

Mathematics
1 answer:
Svet_ta [14]2 years ago
4 0

The sum of the length of the two sides of the triangle must be greater than the length of the third side. None of the triangles is formed. Then option A is correct.

<h3>What is the triangle?</h3>

Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.

The sides of the triangle are 4.7 m, 1.6 m, and 2.9 m.

The condition will be

1.6 + 2.9 \ngtr  4.7

We know that the sum of the length of two sides of the triangle must be greater than the length of the third side.

Hence, none of the triangles is formed.

Thus, option A is correct.

More about the triangle link is given below.

brainly.com/question/25813512

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3 years ago
Pre-calc<br> Evaluate f(2) using substitution:<br> f(x) = 2x^3 – 3x^2– 18x-8
krek1111 [17]

Answer:

f(2) = -40

Step-by-step explanation:

Just substitute x=2 into the function:

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f(2) = 2(8) - 3(4) - 36 - 8

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8 0
2 years ago
Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.
GREYUIT [131]

Answer:

y=\dfrac{1}{1-Ke^{-t}}

Step-by-step explanation:

Given

The given equation is a differential equation

\dfrac{dy}{dt}=y-y^2

\dfrac{dy}{dt}=-(y^2-y)

By separating variable

⇒\dfrac{dy}{(y^2-y)}=-t

\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt

Now by taking integration both side

\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt

⇒\ln (y-1)-\ln y=-t+C

Where C is the constant

\ln \dfrac{y-1}{y}=-t+C

\dfrac{y-1}{y}=e^{-t+c}

\dfrac{y-1}{y}=Ke^{-t}

y=\dfrac{1}{1-Ke^{-t}}

from above equation we can say that

When t  will increases in positive direction then e^{-t} will decreases it means that {1-Ke^{-t}} will increases, so y will decreases. Similarly in the case of negative t.

4 0
3 years ago
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