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zloy xaker [14]
4 years ago
10

One number is 2 more than another. The difference between their squares is 32. What are the numbers

Mathematics
1 answer:
Oksana_A [137]4 years ago
8 0
Let x represent one number. Then the other number is x + 2. Calculation: (x + 2)2 - x2 = 32 x2 + 4x + 4 - x2 = 32 Combine terms: 4x = 28 x = 7 One number is 7. The other number is, 7 + 2, or 9. Questions?
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Step-by-step explanation:

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Please solve it and show a graph
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Step-by-step explanation:

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3 years ago
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What is the completely factored form of f(x)=x3−7x2+2x+4?
sladkih [1.3K]

Answer:

The Factored form is

f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )

Step-by-step explanation:

Given;

f(x)=x^{3} -7\times x^{2} +2x+4

To solve for x  we factorize the right side  of

f(x)=x^{3} -7\times x^{2} +2x+4

Let Substitute x for various values to check whether remainder is zero.

f(1)=1^{3} -7\times 1^{2} +2\times 1+4

Hencex-1 is a factor of the function.

Do synthetic division to find the quotient

1    1  -7  2   4

          1 -6 -4

  _____________________

      1  -6 -4 0

We get remainder 0 and quotient as,

x^{2} -(6\times x)-4

By using Quadratic Formula;

x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a}

Plug 'a' , 'b' and 'c' value from x^{2} -(6\times x)-4 equation,

x=\frac{-(-6)\pm\sqrt{-6^{2}-(4\times1\times -4 )} }{2\times1}

x=\frac{6\pm\sqrt{36+16 } }{2}

x=\frac{6\pm\sqrt{52} }{2}

x=3+\sqrt{13} and x=3-\sqrt{13}

The values of 'x' are 1 , 3+\sqrt{13} and   3-\sqrt{13}

So the Factored form is

f(x)=(x-1)(x-3-\sqrt{13} )(x-3+\sqrt{13} )

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3 years ago
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Romashka [77]
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Nadya [2.5K]

Answer and Step-by-step explanation:

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