Answer: Move terms to the left side−52+3=−9−5x2+3x=−9−52+3−(−9)=0−
Common factor−52+3+9=0−5x2+3x+9=0−(52−3−9)=0
Divide both sides by the same factor−(52−3−9)=0−(5x2−3x−9)=052−3−9=0
Solution=3±321 over 10
Step-by-step explanation:
For Q3, you can subsitute x = 2 and y = 5 into the systems
-5(2) + 5 = -5
so it's a solution for the first system
-4(2)+2(5) = 2
it's also a solution for the second system
C is the answer because it is
H = V/bl. You just cross multiply
