Answer:
6x² – 10y² + 2xy + 10
Step-by-step explanation:
We'll begin calculating the sum of
x² + 3y² – 6xy and 2x² – y² + 8xy + 8
This can be obtained as follow:
... x² + 3y² – 6xy
+ 2x² – y² + 8xy + 8
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3x² – 2y² + 2xy + 8
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Next, we shall determine the sum of:
–3x² + 4y² + 3 and 4y² – 5
This can be obtained as follow:
–3x² + 4y² + 3
+ 4y² – 5
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–3x² + 8y² – 2
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Finally, we shall subtract the sum of:
–3x² + 4y² + 3 and 4y² – 5
from the sum of:
x² + 3y² – 6xy and 2x² – y² + 8xy + 8
This can be obtained as follow:
.. 3x² – 2y² + 2xy + 8
– (–3x² + 8y² – 2)
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6x² – 10y² + 2xy + 10
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<span>$125 is to be paid during the 6th month.</span>
<span>
The vertices of a polygon are given as follows: P(-2,4), Q(4,2), R(4,0); S(-12,0); k = 0.5 Find the coordinates of the vertex P' of the image after a dilation having the given scale factor. Type your answers as a coordinate pair in this format: (x,y)</span>
Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
