MISSING DETAILS
Yoko's fish tank has 17 liters of water in it. She plans to add 5 liters per minute until the tank has at least 57 liters. What are the possible numbers of minutes Yoko could add water?
Answer:
Minutes = 8 minutes
Step-by-step explanation:
Topic: Inequality
Given:
Available Size of water = 17 liters
Increment = 5 liters/minute
Size of water needed = At least 57 liters
Putting the above together, as have
17 + 5m > 57
where m represents total minutes and > represent at least
Solving the Inequality
5m > 57 - 17
5m > 40 ------ Divide through by 5
5m/5 > 40/5
m > 8
So, Yoko will need to add water for at least 8 minutes before she fills her tank to 57 liters.
•sum of the angles in a triangle = 180°
•sum of the angle in a quadrilateral = 360°
•opposite angles are equal
•for two parallel lines and a transversal, corresponding angles are equal, and alternate angles are equal.
•If it already has an angle for a triangle subtract that by 180 and divide it by two you have the other two angle, if you already have two angles on a triangle add those together and subtract from 180 thats the last angle, same for a quadrilateral but you subtract by 360 instead.
X = 3.5.....this is a vertical line that never crosses the y axis. It crosses the x axis at 3.5......so the x int is : (3.5,0)
y = -6.5...this is a horizontal line which never crosses the x axis. It crosses the y axis at -6.5....so the y int is (0,-6.5)
Answer:
•26.376 units
•23.236 units
•34.54 units
•59.66 units
Step-by-step explanation:
The formula for the circumference of a circle is ...
C = 2πr = πd
C = 2(3.14)r = 6.28r or C = 3.14d
where r is the radius and d is the diameter.
Put the given radius or diameter into the relevant formula and compute the product. The results are all in "units".
r = 4.2 ⇒ C = 6.28×4.2 = 26.376
d = 7.4 ⇒ C = 3.14×7.4 = 23.236
d = 11 ⇒ C = 3.14×11 = 34.54
r = 9.5 ⇒ C = 6.28×9.5 = 59.66
Answer:
- using the rule given: 2.5
- using an exponential rule: 7
Step-by-step explanation:
Evaluating the linear rule given, for n = 1, we have ...
a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5
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We suspect you may intend the exponential function ...
an = 7(1/2)^(n-1)
Then, for n = 1, we have ...
a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7
_____
When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.
