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kirill115 [55]
2 years ago
12

You invest $40,000 in two funds paying 4% and 52% simple interest. The total annual interest is $2080. How much do you invest in

each fund?
4% fund:
52% fund:
Mathematics
1 answer:
natali 33 [55]2 years ago
6 0

9514 1404 393

Answer:

  • 4% fund: $39,000
  • 52% fund: $1000

Step-by-step explanation:

Let x represent the amount invested at 52%. Then (40000-x) is the amount invested at 4%. The total annual interest is ...

  0.52x +0.04(40000-x) = 2080

  0.48x = 480 . . . . . . . . . subtract 1600, simplify

  x = 1000 . . . . . . . . . divide by 0.48

Then the amounts invested in each fund are ...

  4% fund: $39,000

  52% fund: $1000

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snow_tiger [21]
By making a line plot you first make a frequency table then you make the line plot
but with fractions u dont make a frequency table you just ordedr the fractions least to greatest i think

5 0
3 years ago
A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

(0.02 g/L) * (1000 L) = 20 g

of chlorine. Let <em>c</em> (<em>t</em> ) denote the amount of chlorine (in grams) in the tank at time <em>t </em>.

Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

which is a linear equation. Move the non-derivative term to the left, then multiply both sides by the integrating factor 1/(200 - 5<em>t</em> )^(5/3), then integrate both sides to solve for <em>c</em> (<em>t</em> ):

\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

7 0
3 years ago
Lucy made $65 for 5 hours of work.
shusha [124]

Answer:

169

Step-by-step explanation:

65 divided by 5 to get 13

and multiply that with 13

like this: 13x13

to get 169

6 0
3 years ago
Read 2 more answers
Can I please get some help
Nitella [24]

Answer:

f(3) = 3\\g(2) = -3\\g(\frac{1}{2}) = 1\\f(2) = \frac{2}{3}\\g(-2) = 0\\f(\pi) = 2\\

Step-by-step explanation:

The functions are given f and g using coordinates.

Whenever we will ask for f(a), we look for "a" in the x coordinate of the function f and find the corresponding value. THAT IS THE ANSWER.

If we ask for g(b), we look for "b" in the x coordinate of the function g and find the corresponding value. THAT IS THE ANSWER.

So,

f(3) = 3\\g(2) = -3\\g(\frac{1}{2}) = 1\\f(2) = \frac{2}{3}\\g(-2) = 0\\f(\pi) = 2\\

5 0
3 years ago
A decorative steel is shown and it is made from circular circle and 6 stems.
STALIN [3.7K]

The total length of the steel used in the frame is 270 cm, if the decorative steel up of 6 stems and each stem is 45 cm.

Step-by-step explanation:

The given is,

           Decorative steel made from circular circle of 6 stems

           The length of the stem is 45 cm

Step:1

         We need to find the total length of the steel used in the decorative steel,

          Let,  T - Total length of the steel

                  L - Length of the stem

                  n - Number of stems used in steel frame

Step:2

       Formula to find the total length of the steel is,

                            T= l × n

       From given,

                  l = 45 cm

                 n = 6 stems

       Substitute the values in formula,

                          T = ( 45 × 6 )

                              = 270

                        T = 270 cm

Result:

         The total length of the steel used in the frame is 270 cm.

5 0
3 years ago
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