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3 years ago

Solve for x 2|x-6|+14=38

Mathematics

1 answer:

ale4655 [162]3 years ago

4 0

Answer:

x=18 x=-6

Step-by-step explanation:

2|x-6|+14=38

The first step is to isolate the absolute value

Subtract 14 from each side

2|x-6|+14-14=38-14

2|x-6|=24

Divide by 2 on each side

2/2|x-6|=24/2

|x-6| = 12

Now we can seperate the absolute value into two parts, the positive and the negative

x-6 =12 x-6 = -12

Add 6 to each side

x-6+6 =12+6 x-6+6 = -12+6

x=18 x= -6

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What is perpendicular to y=1/3x+6 and passes through the point (2,-3)

defon

Answer:

y = -3x + 3

Step-by-step explanation:

Perpendicular slope: -3

y -(-3)= -3(x-2)

y+3= -3x + 6

y = -3x + 3

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2 years ago

Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

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2 years ago

Tim typed a 46-word paragraph in 3/4 of a minute. What is his typing speed per minute?

Rudik [331]

Answer: 61.33333.... wpm

Step-by-step explanation:

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2 years ago

What is the answer 27x^3-1=0

chubhunter [2.5K]