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andrezito [222]
3 years ago
15

Solve for x 2|x-6|+14=38

Mathematics
1 answer:
ale4655 [162]3 years ago
4 0

Answer:

x=18   x=-6

Step-by-step explanation:

2|x-6|+14=38

The first step is to isolate the absolute value

Subtract 14 from each side

2|x-6|+14-14=38-14

2|x-6|=24

Divide by 2 on each side

2/2|x-6|=24/2

|x-6| = 12

Now we can seperate the absolute value into two parts, the positive and the negative

x-6 =12          x-6 = -12

Add 6 to each side

x-6+6 =12+6     x-6+6 = -12+6

x=18                    x= -6

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Answer:

150 miles

Step-by-step explanation:

let m represent miles

$70 + .70m = $40 + .90m

subtract 40 from each side

$30 + .70m = .90m

subtract .70m from each side

$30 = .20m

divide both sides by .20

150 = m

5 0
3 years ago
What is the completely factored form of x4 + 8x2 – 9? (x + 1)(x – 1)(x + 3)(x + 3) (x+1)(x+1)(x+3){x^2+9} (x2 – 1)(x + 3)(x – 3)
Y_Kistochka [10]

Answer:

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Step-by-step explanation:


5 0
3 years ago
Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit
natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.  

Let  

a,b,c be the lengths of the sides of a triangle.  

The area is given by:

A=\sqrt{p(p-a)(p-b)(p-c)}

where

p is half the perimeter

p=\frac{a+b+c}{2}

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}

d=\sqrt{(-4)^{2}+(0)^{2}}

dAB=4\ units

step 2

Find the distance BC

d=\sqrt{(-2+3)^{2}+(1+2)^{2}}

d=\sqrt{(1)^{2}+(3)^{2}}

dBC=\sqrt{10}\ units

step 3

Find the distance AC

d=\sqrt{(-2-1)^{2}+(1+2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

dBC=\sqrt{18}\ units

step 4

a=AB=4\ units

b=BC=\sqrt{10}\ units

c=AC=\sqrt{18}\ units

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p=\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units

Find the area

A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}

A=\sqrt{5.7(1.7)(2.54)(1.46)}

A=\sqrt{35.93}

A=6\ units^{2}

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3 years ago
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kirza4 [7]

Answer:

Step-by-step explanation:

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