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qaws [65]
3 years ago
12

Solve the following equation algebraically: -16= 16x^2 how many solutions does this equation have?

Mathematics
1 answer:
OLga [1]3 years ago
3 0
The answer is x= i, and -i. So there is 2 answers.
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Lines p and q are crossed by transversal s. Classify 1 and 5
allsm [11]

Answer:

corresponding angles

Step-by-step explanation:

5 0
3 years ago
Explain why the triangles are similar. Then find the value of x.
djyliett [7]
Answer: Choice A) AA postulate; 18

---------------------------------------------------------------------------------------

Work Shown:

The triangles are similar to each other due to the AA (angle angle) postulate. The top angles are overlapping or shared angles. So that's the first pair. The second pair of angles is either bottom pair of angles, from the fact that corresponding angles are congruent. This is only true if the lines are parallel.

Due to the similar triangles, we can set up the proportion and solve for x
8/(8+4) = 12/x
8/12 = 12/x
8*x = 12*12 ... cross multiply
8x = 144
x = 144/8
x = 18

8 0
3 years ago
Can someone please help me i don’t understand it
forsale [732]

Answer:

d= bv + r

Treat it like you would a normal equation. Multiply by b and add r to isolate d.

5 0
3 years ago
What is the solution to the equation?<br> -4 = 1<br> .<br> Enter your answer in the box.<br> X=
beks73 [17]

Step-by-step explanation:

I'm not sure about my answer

6 0
2 years ago
You have a jar of jelly beans in front of you
Zepler [3.9K]

Answer: The probability of selecting either a lime or bubble gum followed by a papaya is 425/2209

Step-by-step explanation:

Since, there are four types of items in the jar, namely- lime, papaya, mango and bubble gum that have quantities of 12, 17, 5 and 13 respectively. Before finding the probabilities, we first add up the quantities or number of different items in the jar.

12 + 17 + 5 + 13 = 47 in total.

Since lime is 12 in number, the probability of selecting a lime is = 12/47.

Bubble gums are 13 in number, so the probability of selecting a bubble gum = 13/47.

Then the probability of selecting either a lime or a bubble gum is the addition of the probabilities of selecting a lime and selecting a bubble gum:

= 12/47 + 13/47

= 25/47.

Again, the probability of selecting a papaya is =

number of papaya/total number of items

= 17/47

If the system is with replacement, then the probability of selecting a lime or bubble gum followed by a papaya is:

= Probability of selecting a lime or bubble gum × Probability of selecting papaya

= 25/47 × 17/47

= 425/2209

The probability of selecting a lime or bubble gum followed by a papaya is 425/2209

7 0
3 years ago
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