The solution of 
are 1 + 2i and 1 – 2i
<u>Solution:</u>
Given, equation is
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
<em><u>Let us determine the nature of roots:</u></em>
Here in a = 1 ; b = -2 ; c = 5
Since 
, the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,
On solving we get,
we know that square root of -1 is "i" which is a complex number
Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Answer:
Step-by-step explanation:
Answer:
NOt finished
Step-by-step explanation:
PAGE 1
1.) enlargement b/c the number is more that 1
2.) reduction b/c the number is less than 1
3.) enlargement b/c the number is more than 1
4.) reduction b/c the number is less than 1
5.) reduction k = 1/3
6.) enlargement k = 5/2 or 2.5
PAGE 2
7.) reduction k = 1/3
8.) enlargement k = 2
PAGE 3
Screen shot
PAGE 4
screen shot
PAGE 5
screen shot
I WILL DO THE SCREENSHOTS TOMORROW
When you reflect a diagonal over a line of symmetry, the diagonal will land perfectly on the other diagonal (and vice versa). This suggests that one diagonal is a mirror copy of the other.
Another way to put it: The vertex points of the rectangle will swap when we reflect over a line of symmetry. A diagonal is simply the opposite vertex points joined together. So this is why the diagonals swap places (because the vertices line up perfectly when you apply the reflection).
