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Norma-Jean [14]

3 years ago

8

Cory has 20 crayons. He wants to give the same number of crayons to each of his friend. Write 2 different questions about Cory'

s crayons that can be answered using division

1 answer:

SpyIntel [72]3 years ago

8 0

Answer:

Step-by-step explanation: how many frenis are there?

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Find the HCF of 168 and 196.

yan [13]

Answer:

The HCF of 168 & 196 is 28

Step-by-step explanation:

The factors of 168 are: 1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168

The factors of 196 are: 1, 2, 4, 7, 14, 28, 49, 98, 196

The highest factor that both 168 and 196 share is 28

Hope this helps :D

3 0

3 years ago

Read 2 more answers

In 2014, adele sold 2,500,000 records. In 2015, she sold 90% of the number of records she sold in 2014. In 2016, she sold 80% of

Alla [95]

She sold 70% bc 100% - 90% - 80% -70%

8 0

2 years ago

Read 2 more answers

If I have a 62% in a class, what percentage do I need to get on a 50% weighted test grade to have at least a 70% in the class?

Nastasia [14]

Answer:

78%

Step-by-step explanation:

70 = 0.50 (62) + 0.50 (x)

70 = 31 + 0.5x

39 = 0.5x

x = 78

You must get at least a 78% on the test to have at least 70% in the class.

3 0

3 years ago

Write "100 decreased by a number k" as an algebraic expression.

shtirl [24]

Answer: 2 or B hope this helped!

5 0

3 years ago

Read 2 more answers

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment. Find the margin of error for the 95% confiden

Vlad [161]

Answer:

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.

This means that $n = 2161, \pi = \frac{1214}{2161} = 0.5618$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{0.5618*0.4382}{2161}}$

$M = 0.0209$

The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.

4 0

3 years ago