Yes...the person's hypothesis could be correct.
1.)11x^2-3x
2.)8x+1-x^2
3.)-x^2-x+8
4.)-2y+10-x^2
Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Step-by-step explanation:
<u>step 1:-</u>
Given sample size n=200
of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week
Population proportion of employed individuals who work at home at least once per week P = 
Q=1-P= 1-0.205 = 0.705
<u>step 2:-</u>
Now 
=0.0015
<u>step 3:-</u>
<u>Confidence intervals</u>
<u>using formula</u>


=0.20113,0.20887[/tex]
<u>conclusion:</u>-
99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week
//0.20113,0.20887[/tex]
Answer:
12+36p
Step-by-step explanation:
First distribute the 2 to binomial then the 6.
6(2+6p)
12+36p
7 would probably end up being 6 12/12 if I am doing his correctly.