Both A and C would be solutions to the equation.
In order to solve for this you must first get the equation equal to 0.
2x^2+5x+8=6 ----> subtract 6 from both sides
2x^2 + 5x + 2 = 0
Now knowing this we can use the coefficients of each one in descending order of power as a, b and c.
a = 2 (because it is the coefficient to x^2)
b = 5 (because it is the coefficient to x)
c = 2 (because it is the end number)
Now we can plug these values into the quadratic equation.
or -1/2 for the first answer
or -2 for the second answer
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
You didn't include the costs of doing repairs at both computer repair firms. I fixed that for you.
ABC Tech ------- $20 service charge plus $15 per hour.
Tech squad ------- $30 service charge plus $10 per hour.
Answer:
Steven's estimate of the repair time is 2 hours.
Step-by-step explanation:
Now in this case, we were told that ABC Tech normally charges $20 service charge and $15 per hour of computer repair service. The second tech firm charges $30 service charge and $10 per hour for computer repair service. We are now simply required to find out or calculate the number of hours of computer repair service whereby the cost of doing repairs at both tech firms become equal.
Let us use "x" to represent that unknown number of hours. The equation needed to calculate this is:
20 + 15x = 30 + 10x
We then pair like terms
15x - 10x = 30 - 20
5x = 10
x = 10/5
x = 2
Therefore the number of hours of computer repair service whereby the cost of doing repairs at both tech firms become equal is 2 hours.
Answer:
38 kids on each team about.
I am Not 100% sure but I hope this Helps!
So D.
40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.
Hope this helps!
