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Maksim231197 [3]
2 years ago
10

45 miles divided by 1 hour and 45 minutes

Mathematics
2 answers:
Maurinko [17]2 years ago
8 0

Answer:

(45 miles) / ((1 hour) + (45 minutes)) =

11.4953143 m / s

Step-by-step explanation:

Nikitich [7]2 years ago
8 0

Answer:

25.71 mph

Step-by-step explanation:

45 miles in  1.75 hours

45 miles /1.75  hours =  25.71 mph

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Evaluate the expression.<br><br> |3| + |-1|<br> A) -2<br><br> B) -4<br><br> C) 2<br><br> D) 4
Kisachek [45]

Answer:

D) 4

Step-by-step explanation:

|3| + |-1| = 3 + 1 = 4 \\

4 0
3 years ago
The following table shows a proportional relationship between x and y.
RUDIKE [14]

Answer:

Assume x is directly proportional to y :

y \:  \alpha  \: x \\ y = kx

when y is 9, x is 2:

substitute to find value of k :

9 = (k \times 2) \\ k =  \frac{9}{2}

Therefore, equation is:

{ \boxed{ \boxed{2y = 9 x}}}

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3 years ago
I help I’ve been stuck on this one
nlexa [21]

202 + 156 = 358
500 - 358 = 142
the answer is A. 142
7 0
3 years ago
Quesuon Z: 2 PES
cricket20 [7]

Answer:

124 ft2

Step-by-step explanation:

The yard is a 12ft square so the length and width would both be 12ft. You multiply the length and width of the yard to get the area of the yard so 12x12=144. You have the length and width of the flower bed so 5x4=20. Once you have the area of both you can subtract the area the flower bed takes up of the lawn. 144-20=124 ft2.

5 0
3 years ago
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
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