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sergeinik [125]
3 years ago
11

Fill in the table using this function rule. y = 5x+4

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
No idea man

Explanation: I don’t man I just wang pints
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What is a common denominator for 1/4 and 5/6!?!? PLEASE HELP!!!!!!
UNO [17]
A common denominator for 1/4 and 5/6...
1/4 = 3/12
5/6 = 10/12
the common denominator (LCM) would be 12
5 0
3 years ago
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Find the ​slope-intercept form of the equation of the line that passes through the point P and makes angle with the positive ​x-
SIZIF [17.4K]

Answer:

The answer is "y= -x+7"

Step-by-step explanation:

If \bold{\theta = 135^{\circ}}

point: p=(2,5)

Formula:

\to m= \tan \theta \\\\\to (y-y_1)= m(x-x_1)

\to m= \tan \ 135^{\circ} =  -1\\\\\to x_1= 2\\\\\to y_1=5

Put the value in the above formula:

\to y- 5 = -1(x-2)\\\\\to y- 5 = -x+2\\\\\to x+y = 5+2\\\\\to x+y=7

\to y= -x+7

3 0
3 years ago
Please help this is timed test ❤️
drek231 [11]

Answer:

A.

Step-by-step explanation:

6 0
2 years ago
Use the graph of y = f(x) to graph y= f(x) + 2
Mama L [17]

Explanation:


Draw a dot 2 units above each dot shown on the graph. Connect the dots in the same way they are connected here.


f(x)+2 simply translates the curve up 2 units.

7 0
3 years ago
Swimming speed of salmon. The graph is showed below shows the influence of the temperature T on the maximum sustainable swimming
Doss [256]

Answer:

Here we have the relation between the speed of the salmon and the temperature.

a) the relation dS/dT tell us how the speed of the salmon changes as the temperature changes, and the units should be (if speed is m/s and temperature is in °C )

[dS/dT ] = [m/s*°C ].

b) I can not do a draw of the figure, but i can give a aproximation.

For T = 18°C, we can see that we are around the maximum of the curve, this means that around this point we will find the zero in the first derivate.

then S'(18) ≈ 0 m/s*°C

this means that around this point the changes are small.

for T = 10°C

Around this region, we can see almost a linear behavior.

so we can take a range of +-2°C

S(12°C) = 25m/s

S(8°C) = 20m/s

then the slope can be obtained using the relation:

S = (Y2 - Y1)/(X2 - X1) where this is the slope for the line that goes trough the pairs. (X1, Y1) and (X2, Y2)

S = (25 - 20)/(12 - 8) = 5/4

then we have that S´(10°C) ≈ 5/4 m/s*°C

Those two results are approximations, you may find better approximations by doing this with a ruler and drawing the tangents.

5 0
3 years ago
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