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Naya [18.7K]
3 years ago
5

How do I factor (x^2 + 1)^1/2 +2(x^2 + 1)^1/2

Mathematics
1 answer:
professor190 [17]3 years ago
5 0
(x^{2} + 1)^{ \frac{1}{2}} + 2((x^{2} + 1)^{ -\frac{1}{2}}) \\\\ Take \ out \ (x^{2} + 1)^{ \frac{1}{2}} \ like \ so: \\\\ (x^{2} + 1)^{ \frac{1}{2}}(1 + 2(x^{2} + 1)^{ -1}) \\\\ = (x^{2} + 1)^{ \frac{1}{2}}(1 + \frac{2}{(x^{2} \ + \ 1)}) \\\\ = (x^{2} + 1)^{ \frac{1}{2}}(\frac{2 \ + \ (x^{2} \ + \ 1)}{(x^{2} \ + \ 1)}) \\\\ = (x^{2} + 1)^{ \frac{1}{2}}(\frac{(x^{2} \ + \ 3)}{(x^{2} \ + \ 1)}) \\\\ = \frac{(x^{2} \ + \ 1)^{ \frac{1}{2}}(x^{2} \ + \ 3)}{(x^{2} \ + \ 1)} \\\\
This is what I would think to do with such an expression;
It should be alright to leave it as it is on the last line as this should be its simplest form;
But, you could write it out as:
\frac{(x^{2} \ + \ 3)}{(x^{2} \ + \ 1)^{ \frac{1}{2}}} \\\\
= \frac{(x^{2} \ + \ 3)}{ \sqrt{(x^{2} \ + \ 1)}}
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7 0
3 years ago
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Which inequality is equivalent to -6x ≥ 30?
liq [111]
Hey there!

Our goal here is to isolate the variable, x. In order to do this following the dividing and algebraic property of equality (which states that the equation remains equal if you do the same thing to both sides) , we must divide both sides by the coefficient of x, -6. That gives us: 

-6x/-6 ≥ 30/-6

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</span>
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8 0
3 years ago
What is the determinant of matrix |-8|?​
ivanzaharov [21]

Given:

The matrix is [-8].

To find:

The determinant of given matrix, i.e, |-8|.

Solution:

If a matrix is A of order 1\times 1, then the value of the determinant of that matrix is equal to the element of that matrix.

For example: Let A be the matrix of order 1\times 1.

A=[a]

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|A|=a

The given matrix is [-8]. So, the  determinant of given matrix, i.e, |-8|, is

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Therefore, the value of determinant of given matrix is -8.

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Write the prime factorization for 65,169
posledela

Let's try to find some primes that divide this number.

The number is not divisible by 2, because it is odd.

The number is divisible by 3 though, because the sum of its digits is:

6+5+1+6+9=27=3\cdot 9

So, we can divide the number by 3 and keep going with the factorization:

65169\div 3 = 21723

This number is again divisible by 3, because

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We have

21723\div 3 = 7241

This number is no longer divisible by 3. Let's go on looking for primes that divide it: 5 doesn't because the number doesn't end in 0 nor 5. This number is not divisible by 7 or 11 either (just try). It is divisible by 13 though: we have

7241\div 13 = 557

And 557 is prime, so we're done. This means that the prime factorization of 65169 is

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