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MA_775_DIABLO [31]
3 years ago
8

Write the slope-intercept form of the equation of each line.

Mathematics
1 answer:
miskamm [114]3 years ago
7 0

Answer:

y = 3x + 2

Step-by-step explanation:

Let's identify two clear points on this line. I can see (0, 2) and (-1, -1)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(-1 - 2) / (-1 - 0)

Simplify the parentheses.

= (-3) / (-1)

Simplify the fraction.

-3/-1

= 3

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 3x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the first point (0, 2). Plug in the x and y values into the x and y of the standard equation.

2 = 3(0) + b

To find b, multiply the slope and the input of x(0)

2 = 0 + b

Now, we are left with 0 + b.

2 = b

Plug this into your standard equation.

y = 3x + 2

This is your equation.

Hope this helps!

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Answer:

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Step by step

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a)

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b)

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c)

\frac{13\pi}{6}=390^\circ=360^\circ+30^\circ, then it is in the first cuadrant and the reference angle is 30^\circ =\frac{\pi}{6}.

d)

\frac{8\pi}{6}=240^\circ and it is in the third cuadrant, then its reference angle is 240^\circ -180^\circ=60^\circ=\frac{\pi}{3}

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Answer:

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Step-by-step explanation:

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CHECK THE ATTACHMENT FOR THE FIQURE

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