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maks197457 [2]
3 years ago
11

Point m is the center of a regular octagon what is one portion of octagon

Mathematics
1 answer:
Ilya [14]3 years ago
7 0
I believe the answer would be one eighth or 1/8
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What is the equation of the line passing through the point (4, 5) that is parallel to the line with the equation
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Answer:

y=2x-3

Step-by-step explanation:

1. find the slope

6x-3y=21

-3y=-6x+21 divide both sides by -3

y=2x-7

slope is 2

2.y-5=2(x-4)

  y-5=2x-8

  y=2x-8+5

  y=2x-3

PARALLEL lines have the same slope

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What is 3/25*2/13 ? <br><br>A 5 2/15 <br><br>B 6 2/15 <br><br>C 7 14/15 <br><br>D 8 1/15
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Add 7 and 3 8ths meters plus 6 and 1 third meters. Does the sum belong to the set of rational number integers or whole numbers?
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A wire is stretched from the ground to the top of an antenna tower. The wire is 15 feet long. The height of the tower is 3 feet
Mariana [72]

The distance d is 9 ft and the height is 12ft.

<h3>How to find the distance and the height?</h3>

Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.

The height is one cathetus and the distance is the other catheti.

Let's define:

  • h = height
  • d = distance.
  • hypotenuse = 15ft

We know that the height of the tower is 3 ft larger than the distance, then:

h = d + 3ft

Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.

Then:

d^2 + (d + 3ft)^2 = (15ft)^2

Now we can solve this equation for d:

d^2 + d^2 + 6ft*d + 9ft^2 = (15ft)^2\\\\2d^2 + 6ft*d - 216 ft^2 = 0\\\\d^2 + 3ft*d - 108ft^2 = 0

Then the solutions are:

d = \frac{-3ft \pm \sqrt{(3ft)^2 - 4*(-108ft^2)} }{2} \\\\d = \frac{-3ft \pm 21ft }{2}

We only take the positive solution:

d = (-3ft + 21ft)/2 = 9ft

And the height is 3 ft more than that, so:

h = 9ft + 3ft = 12ft

The distance d is 9 ft and the height is 12ft.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

8 0
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