Which expressions are differences of squares?
2 answers:
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Answer:
The function touches the damping factor
at x= and x=
The x-intercept of f(x) is
at x=
Step-by-step explanation:
Given function is f(x)= and damping factor as y=
and y=
To find when function touches the damping factor:
For f(x)= and y=
Equating the both the equation,
x=
For f(x)= and y=
Equating the both the equation,
x=
Therefore, The function touches the damping factor x= and x=
To find x-intercept of f(x):
For x-intercept, y=0
f(x)=
y=
Hence, is always greater than zero.
Therefore,
x=
Thus,
The x-intercept of f(x) is at x=
Given that,
An equation : -9c² +2c +3 = 0
To find,
Find the value of x.
Solution,
We have, -9c² +2c +3 = 0
We can solve it using the formula as follows :
Here, a = -9, b = 2 and c =3
Put the values,
So, the solution are -0.47 and 0.69.
My apologies on answering late...
Same situation as the previous problem, but this time, all you need to do is state the degree of the angle instead of just providing the angle itself.
ΔABC ≅ ΔDEF
Now, we can see that ∠C ≅ ∠F. Using this information, we can find ∠C on the first triangle ( which is ° ).
Since ∠C ≅ ∠F,
m∠F is °.
Hope I caught your question in time!
Have a good one! If you need anymore help, let me know.