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Answer:
Sum of the Roots = 37
Product of the Roots = 27
Step-by-step explanation:
Here, the given expression is 
Now the general Quadratic Equation is of the form:

Here, Sum of the Roots = 
and the Product of the Roots = 
So, comparing the general equation with the given equation, we get:
a = 1, b = -37 and c = 27
So, Sum of the Roots =
= 37
and the Product of the Roots =
= 27
Answer:
-3.5
Step-by-step explanation:
We have to find the distance between x and z along the y-axis.
This will be: 5 - -6 = 11 units
1/5 th of 11 = 1/5 × 11
= 11/5
= 2 1/5 = 2.5
Now add 2.5 to -6
2.5 + -6 = -3.5
The value of y = -3.5
Answer:
-37
Step-by-step explanation:
2 x 3 + 57 -100
we do something called pemdas
We start with multiplying first
2 x 3 = 6
Then we do addition
6+57 = 63
then we subtract
63- 100 = -37
Answer:
The final pressure of the gas when its temperature returns to its initial value
Pa.
Step-by-step explanation:
Given : An ideal gas is confined within a closed cylinder at a pressure of
Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.
To find : What is the final pressure of the gas when its temperature returns to its initial value?
Solution :
Since the temperature is constant
.
The relation between P and V is given by,

....(1)
The piston moves until the volume of the gas is reduced to one-ninth of the initial volume i.e. 
or 

Substitute in equation (1),
The final pressure of the gas when its temperature returns to its initial value
Pa.