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OlgaM077 [116]
2 years ago
14

Write an equation in slope-intercept form then Graph. 3x-6y=-12

Mathematics
1 answer:
algol [13]2 years ago
7 0
<h3><u>y = 1/2x + 2 is the given equation in slope-intercept form.</u></h3>

3x - 6y = -12

Currently, this is in standard form.

In order to convert this to slope-intercept form, we need to isolate y.

Add 6y to both sides.

3x = -12 + 6y

Add 12 to both sides.

3x + 12 = 6y

Divide both sides by 6.


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Step-by-step explanation:

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Write equation of the line below​
vodka [1.7K]

Hi there!

We are given two ordered pairs which are:

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  • (5,4)

If you are curious how do I get these ordered pairs, they come from those two big circles or dots. x and y make relation and can be written as (x,y).

1. Find the slope

  • Yes, our first step is to find the slope of a graph if you want to find an equation. You may be curious how to find that right? No worries! We have got a special formula for you to find the slope!

\large \boxed{m =  \frac{y_2 - y_1}{x_2 - x_1} }

Since we have two given points, we can substitute them in the formula.

\large{m =  \frac{4 - 0}{5 - 0} } \\  \large \boxed{m =  \frac{4}{5} }

2. Form an equation.

  • Since we have finally found, got or evaluated the slope. Next step is to find the y-intercept. Oh! Before we get to form an equation, do you know the slope-intercept form? We will be using that linear equation form since it is commonly used in the topic.

\large \boxed{y = mx + b}

Where <u>m</u><u> </u><u>=</u><u> </u><u>s</u><u>l</u><u>o</u><u>p</u><u>e</u> and <u>b</u><u> </u><u>=</u><u> </u><u>y</u><u>-</u><u>i</u><u>n</u><u>t</u><u>e</u><u>r</u><u>c</u><u>e</u><u>p</u><u>t</u><u>.</u> We substitute m = 4/5.

\large{y =  \frac{4}{5} x + b}

Next thing to remember is that when the graph intersects an origin point, b-term or y-intercept would be 0. Therefore b = 0 since the graph intersects (0,0).

\large \boxed{y =  \frac{4}{5} x}

3. Answer

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2 years ago
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Answer:

Step-by-step explanation:

Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.

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From above, we have a power to a power, so, we can think of multiplying the exponents.

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