Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer is B. 48
By circle theorem, the angle at the centre of the circle is twice the angle at the circumference.
Answer: D. (-2,0) and (9,0)
Step-by-step explanation:
When you equate the factors to 0 you get
(X+2) = 0
X = -2
(X-9) = 0
X= 9
Here the Y value is 0 as you find the factors of x when the Y value is 0.
So the answer is (-2,0) and (9,0)
Answer:
16
Step-by-step explanation:
Let the 1st part of your answer be x
, so the 2nd part will be 40-x
. From the given information, we can write the equation: (1/4)x = (3/8) × (40-x)
. We can simplify this into (1/4)x = (120-3x)/8
; 8x = 480-12x
; 8x+12x = 480
; 20x = 480
; x = 480/20; x = 24
Therefore, the 1st part = 24
Plug this into your 40-x equation to get: 40 - 24 = 16
Answer:
6.24
Step-by-step explanation:
A= 18.42g, B = 5.8g,C = 0.75g
Total = 18.42 + 5.8 + 0.75
= 24.97g
Then divided into four equal parts
= 24.97g/4
= 6.2425g
= 6.24g
